Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 11)
11.
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
Answer: Option
Explanation:
Let Abhay's speed be x km/hr.
| Then, | 30 | - | 30 | = 3 |
| x | 2x |
6x = 30
x = 5 km/hr.
Discussion:
209 comments Page 10 of 21.
Asit Kumar Chand said:
2 months ago
30/A-30/B = 2 ---> (1)
30/B-30/2A = 1 ---> (2)
By adding two equations
30/A - 30/2A = 3,
60 - 30/2A = 3,
30 = 6A.
A = 30/6.
A = 5km/h.
30/B-30/2A = 1 ---> (2)
By adding two equations
30/A - 30/2A = 3,
60 - 30/2A = 3,
30 = 6A.
A = 30/6.
A = 5km/h.
(8)
Anonymous said:
1 decade ago
30/x = y+2 ->1 [x=speed,y=time].
30/2x = y-1 ->2.
Now 1-2 we get,
(30/x)-(30/2x) = (y+2)-(y-1).
(30/x)-(30/2x) = 3.
30/2x = y-1 ->2.
Now 1-2 we get,
(30/x)-(30/2x) = (y+2)-(y-1).
(30/x)-(30/2x) = 3.
Abdus samadh said:
1 decade ago
From devi's explanation, after 2nd line((30/X) - (30/2X) = t+2-t+1)
60/2X - 30/2X = 3;
30 = 6X(3 * 2X);
so X=5;
is it right?
60/2X - 30/2X = 3;
30 = 6X(3 * 2X);
so X=5;
is it right?
Monpara Ashvin said:
1 decade ago
30/x = y+2 ->1 [x=speed, y=time].
30/2x = y-1 ->2.
Now 1-2 we get,
(30/x)-(30/2x) = (y+2)-(y-1).
(30/x)-(30/2x) = 3.
30/2x = y-1 ->2.
Now 1-2 we get,
(30/x)-(30/2x) = (y+2)-(y-1).
(30/x)-(30/2x) = 3.
Avigeh said:
7 years ago
Suppose Abhay's speed is -x km/h.
then suppose y is Abhays speed;
(y+2)-(y-1)=3.
30/x-30/2x=3.
(60x-30x)/2x=3.
Ans is 5km/h.
then suppose y is Abhays speed;
(y+2)-(y-1)=3.
30/x-30/2x=3.
(60x-30x)/2x=3.
Ans is 5km/h.
Siva said:
1 decade ago
can u tell me any one ...why the values (30/x)-(30/2x)=(ts+2)-(ts-1) are subtracting?
i.e., between (30/x) and (30/2x)
i.e., between (30/x) and (30/2x)
Ram ji said:
8 years ago
You can use this formula for this type of questions d=(s1*s2)/s1-s2*t.
Here d:distance(30) ,t: time difference( 3).
Here d:distance(30) ,t: time difference( 3).
Abdul quddus said:
6 years ago
S1= s = d/t = d/t+2.
S2 = 2s = d/t-1.
S/2s = 1/t+2/1/t-1.
1/2 = t-1/t+2.
t+2 = 2t-2.
t = 4.
S = D/T = 30/6 = 5.
S2 = 2s = d/t-1.
S/2s = 1/t+2/1/t-1.
1/2 = t-1/t+2.
t+2 = 2t-2.
t = 4.
S = D/T = 30/6 = 5.
Srujana said:
6 years ago
30/x - 30/2x = 3.
Here why should we subtract 30/x - 30/2x and how we will get 3?
Please can anyone explain?
Here why should we subtract 30/x - 30/2x and how we will get 3?
Please can anyone explain?
Rajeshkumar said:
9 years ago
Abhay takes 2 hours and if doubles her speed he takes 1 hour less than Sameer so,
2 - (-1) = 3.
2 - (-1) = 3.
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