Aptitude - Time and Distance - Discussion

Abhay takes 2 times more than Sameer
2x = x.

If Sameer doubles his speed, he would take less than 1hour of Sameer
2 * 2x = 1 - x,
4x = 1 - x,
4x + x = 1,
5x = 1,
x = 1 ÷ 5.
According to question, speed is 1 ÷ 5 is 5.

30/x - 30/2x = 3.
30/x - 15/x = 3.
15/x = 3.
15/3 = x.
5 = x.

Nice explanation & well said @Anand.

If it is asked about Sameer's speed then what would be the answer?

Abhay takes 2 hours and if doubles her speed he takes 1 hour less than Sameer so,

2 - (-1) = 3.

Let time taken by Sameer be "t".

First case: when the time taken by Sameer is "t", time taken by Abhay is "t + 2".

Let the speed of Abhay be "s".

Second case: when the speed of Abhay is "2s" time taken by him is "t - 1".

Now from case one and case two, it can be said as,

S = 30/(x + 2) -----> equation (1).

2s = 30/(x - 1) -----> equation (2).

Now substitute "s" value in equation (2).

Thus we get the value of t = 4 hours.

Now Speed of Abhay = 30/(x + 2) = 30/(4 + 2) = 30/6 = 5 hours.

If the distance is same then,

Sameer's speed = 30/4.
= 7.5 km/hr.

Thanks, @Devi. Very nice explanation.

Thanks @Devi.

Thanks @Devi.