Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = | ![]() |
9 | x 60 | min |
= 10 min. |
| 54 |
Discussion:
207 comments Page 8 of 21.
Ram said:
7 years ago
Let the distance be 270 km.
During normal speed, i.e 54 km/hr. The time taken =5hrs.
And with the average speed of 45 km/hr, the time taken is 6 hrs, i.e 60 minutes more.
My doubt is that these 60 minutes must have been spending in the interval of 5 hrs, i.e 12 minutes per hour.
Why can't the answer be 12 minutes?
During normal speed, i.e 54 km/hr. The time taken =5hrs.
And with the average speed of 45 km/hr, the time taken is 6 hrs, i.e 60 minutes more.
My doubt is that these 60 minutes must have been spending in the interval of 5 hrs, i.e 12 minutes per hour.
Why can't the answer be 12 minutes?
Sahil said:
7 years ago
Let 54 km and 45 km is a distance that travelled by bus in *1hour*.
45 km distances travelled by car in 1 hour due to the stoppage.
If it travels without a stoppage, it would cover in a 45km/ 54kmph = 5/6h.
5*60/6 = 50 min,
60-50 = 10 minutes.
45 km distances travelled by car in 1 hour due to the stoppage.
If it travels without a stoppage, it would cover in a 45km/ 54kmph = 5/6h.
5*60/6 = 50 min,
60-50 = 10 minutes.
Borade vikas said:
7 years ago
How we take the ratio of (9÷54)*60?
Please explain this step.
Please explain this step.
RAJU said:
7 years ago
Bus can cover distance without stops for 60mins(60 * 54) = 3240m.
Bus can cover distance with stops for 60mins (60 * 45) = 2700m.
difference distance = 540m.
Time = distance/speed = 540/54 = 10mins.
Bus can cover distance with stops for 60mins (60 * 45) = 2700m.
difference distance = 540m.
Time = distance/speed = 540/54 = 10mins.
Naidu said:
7 years ago
Well said @Bipana.
ACHYUT KUMAR PATRA said:
7 years ago
I think 10 is the right answer. I agree with the given answer.
Priya said:
7 years ago
Thank you @Lohith.
Lohith said:
7 years ago
We can do this simply by ratios.
Given speeds 54kmph,45kmph ratio:54:45,
Speeds ratio- 6:5.
Times ratio will be- 5:6 (since speed and time are inversely proportional).
In times ratio 1 part difference is there hence in total 6 parts 1 part is stoppage we calculate (1/6)*60=10.
Given speeds 54kmph,45kmph ratio:54:45,
Speeds ratio- 6:5.
Times ratio will be- 5:6 (since speed and time are inversely proportional).
In times ratio 1 part difference is there hence in total 6 parts 1 part is stoppage we calculate (1/6)*60=10.
Raj said:
8 years ago
Thank you @Kunal.
Aman said:
8 years ago
Why is it written 150 instead of 50%?
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