Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = |  |
9 | x 60 |  min |
= 10 min. |
| 54 |
Discussion:
205 comments Page 6 of 21.
KArthik said:
6 years ago
Hey guys, for this we can simply use the proportion method;
60min : 54km :: x min : 9km (product of extremes = product of means)
60*9=54x.
x=(60*9)/54 (9 and 54 will be cancelled by 9 tables)
x=60/6 (60 and 6 will be cancelled by 6 tables)
x=10min.
Therefore, the time taken by train is 10 min.
60min : 54km :: x min : 9km (product of extremes = product of means)
60*9=54x.
x=(60*9)/54 (9 and 54 will be cancelled by 9 tables)
x=60/6 (60 and 6 will be cancelled by 6 tables)
x=10min.
Therefore, the time taken by train is 10 min.
KArthik said:
6 years ago
Thank you @Kushal.
Bantu Venkatesh said:
6 years ago
54km ------------- 60min
45km ------------- ?????.
45/54*60min = 50min.
60min - 50min = 10min.
45km ------------- ?????.
45/54*60min = 50min.
60min - 50min = 10min.
Pallavi said:
6 years ago
We have taken 54 because if we take 45, this is the speed of bus with the stoppage, it has already taken the stop that's why 54 is taken.
Sabbir said:
6 years ago
Travelling difference = 9 km/hr.
Travels 54 km taking 60 mins.
Hence, travels 9 km taking 10 mins.
So, the answer is 10 mins.
Travels 54 km taking 60 mins.
Hence, travels 9 km taking 10 mins.
So, the answer is 10 mins.
Satwik said:
6 years ago
For 1hr ---> 54km.
For how much time with 45km/hr it takes to travel 54km is the total time taken by the bus to travel with stops.
So t=(54/45)*60=72min;.
Its the total time taken subtracting an hour travelled common and we get 12 min.
then how come 10 min be the answer?
For how much time with 45km/hr it takes to travel 54km is the total time taken by the bus to travel with stops.
So t=(54/45)*60=72min;.
Its the total time taken subtracting an hour travelled common and we get 12 min.
then how come 10 min be the answer?
Sasinath said:
6 years ago
54-45 = 9kmph. i.e., the bus would lose 9km in 1 hr.
Let the time bus stops at a time be t. Then the distance bus would lose will be s. Then s will be,
s = v*t = 54*t.
Let a total number of stoppages be x.
Then the total distance lost by the bus in the second case is,
x*s = x*54*t.
x*54*t = 9.
x*t = 1/6.
So in 1 km, t = 1/6 hour = 10 mins.
Let the time bus stops at a time be t. Then the distance bus would lose will be s. Then s will be,
s = v*t = 54*t.
Let a total number of stoppages be x.
Then the total distance lost by the bus in the second case is,
x*s = x*54*t.
x*54*t = 9.
x*t = 1/6.
So in 1 km, t = 1/6 hour = 10 mins.
SWADHIN said:
6 years ago
Very simple, thanks @Prithvi.
Aiswarya said:
6 years ago
Thanks @Prithvi.
Prithvi said:
6 years ago
For 54 km it is 60 min.
For 45 km how much?
54 = 60
45 = x
X = 50, the difference in time 10 min gives us stoppage time.
For 45 km how much?
54 = 60
45 = x
X = 50, the difference in time 10 min gives us stoppage time.
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