Aptitude - Time and Distance - Discussion

Its very simple,

Firstly,
54 - 45 =9 due to stoppages,it covers 9km less.
Time taken to cover 9km = (9/54 x 60) =10mins. And in "1 min there are 60 seconds".

@Shravani.

Here is my explanation for your doubt.

It doesn't represent the actual speed, it includes the stoppages to cover less speed. Using 45kmph does not give us the correct answer that's why we use actual speed to find the time taken.

Due to stoppages, it covers 9 km less.

Time taken to cover 9 km = 9 x 60 min = 10 min.

@All.

Here is my solution;

For me, in 1 hour the bus runs 54 km by the speed of 54km/h excluding stops.
But because of stop time, it runs by a speed 45km/h.
That means 54 km/ times = 45 ( km/h).
So the total times needed is 54/45 = 6/5 h,
And stop time is 6/5 -1 = 1/5h = 12 minutes.

54kmh means it travels 54 kms in one hour when the train runs continuously in that hour. However including stoppages the train travels only 45 km in one hour. Thus in one hour train travels 9 km less due to stoppages.

Thus the time the train stops in an hour is the time it would have used to travel 9kms with the speed of 54kms, which when converted to minutes is equal to 10.

Non stoppages speed= 54kmph,
with stoppages speed= 45kmph.

Reduce speed due to stoppages = 54-45 = 9 kmph.
we need to find the time taken by bus at a stop in each hour i.e t
t = s/v,
t = 9/54 ph ( we take 54 because we are talking about non-stoppages).
= 1/6 *60 min.
=10 min.

@All.

As per my knowledge, to solve this question, we can use the concept of average speed.

Let's denote the time the bus stops per hour as (T) minutes.

The speed without stoppages is 54 kmph, and the speed with stoppages is 45 kmph.

The time taken to cover the same distance without stoppages = 60 minutes.
The time taken to cover the same distance with stoppages = 60 + (T) minutes.

Using the formula for average speed: Average Speed = Total distance/Total time.

We can set up the equations:
54 = Total distance/60
45 = Total distance/(60 + (T)).
Now, solve for (T) minutes to find out how many minutes the bus stops per hour.

Thanks for explaining @Anoo.

Due to stoppages, it covers 9 km less.

Time taken to cover 9 km = 9 x 60 min = 54.

Simple:

The Speed of a bus without a stoppage is 54kmph.
The speed of bus with a stoppage is 45kmph.
So from this, it is clear that the speed of the bus is 54kmph only;
Now think like this;

54 mango costs 60 rs (1hour = 60minutes);
So 1 mango costs (60/54)rs.
Here the bus travels 9 km less in one hour due to stoppings,
Therefore 9 mango costs = (60/54)*9.
i.e. = 10 rs or 10 minutes.