Aptitude - Time and Distance - Discussion

Excluding the stoppages, it is 54kmph. Here the question is about the time taken at every stop, which should be calculated using the speed taken when including the stops, that is 45 kmph. Why is it taken as 54?

Please explain me.

I can't understand why we have taken 54km/hr for calculation. Why not 45km/hr? Anyone, please clarify it.

Speed of bus ->54 km/ hr(without stopping the bus)
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.
(54km/hr - 45 km/ hr = 9km)

So, the distance is 9 km,
We have to find out the time,
T = D/S.
T = 9/54.
T = 1/6 hr.
( 1 hr -> 60 min).
T = 1/6 *60min.
T = 10 min.

Why have we taken the speed of the train without stoppages (that is 54kmph) for calculating the time taken by the bus to cover 9 km?

Anyone, please clarify.

I can't understand. Can anybody explain me?

12 km is the right answer.

See, the problem is simple, but we just require a way of understanding it.

Speed is 54kmph. That is clear. Now it says that due to the inclusion of 'stoppage' it is 45kmph. We need to understand that this just means that it appears to be 45kmph due to stoppage, which further means that where it had the potential of covering 54km in 1hr, it is now covering 45km in 1hr (but the speed is going to remain, just that the bus stops, hence time is consumed there, otherwise the speed is same only).

So (actual speed)*(1hr - time wasted due to stopping) = 45

Actual speed = 54kmph, and the time wasted has to be found out.

1hr - wasted time shows the effective moving time, due to which, while travelling at 54kmph, the bus covered a 45km distance only.

I hope it clears the doubt.

Why we take 54 instead of 45? Please explain.

@Shravani.

Here is my explanation for your doubt.

It doesn't represent the actual speed, it includes the stoppages to cover less speed. Using 45kmph does not give us the correct answer that's why we use actual speed to find the time taken.

Speed of bus ->54 km/ hr(without stopping the bus)
Speed of bus ->45 km/ hr( with stopping the bus)
Excluding - including stoppages.

(54km/hr - 45 km/ hr = 9km)
So, the distance is 9 km,
We have to find out the time,
T = D/S.
T= 9/54.
T= 1/6 hr.
( 1 hr -> 60 min).
T= 1/6 *60min.
T= 10 min.