Aptitude - Time and Distance - Discussion

Thank you @Lohith.

I think 10 is the right answer. I agree with the given answer.

Well said @Bipana.

Bus can cover distance without stops for 60mins(60 * 54) = 3240m.
Bus can cover distance with stops for 60mins (60 * 45) = 2700m.
difference distance = 540m.

Time = distance/speed = 540/54 = 10mins.

How we take the ratio of (9÷54)*60?

Please explain this step.

Let 54 km and 45 km is a distance that travelled by bus in *1hour*.

45 km distances travelled by car in 1 hour due to the stoppage.
If it travels without a stoppage, it would cover in a 45km/ 54kmph = 5/6h.
5*60/6 = 50 min,
60-50 = 10 minutes.

Let the distance be 270 km.
During normal speed, i.e 54 km/hr. The time taken =5hrs.
And with the average speed of 45 km/hr, the time taken is 6 hrs, i.e 60 minutes more.
My doubt is that these 60 minutes must have been spending in the interval of 5 hrs, i.e 12 minutes per hour.
Why can't the answer be 12 minutes?

Simply, the solution is;

60min --> 54km
x min --> 45

>>x=50;

This means with stoppages it is taking 50 min to reach 45km.
but now without stoppage it is taking 60 min so with stoppage it is taking extra 10 min.

See I will reframe the question to understand it in a better way.. Bus has started from point A. there are stops in between till point B so its speed is less i.e. 45km/hr. Now after this point there are no stops so it increases its speed to 54km/hr to reach point C. We have to find the time lapse of distance covered between these two speeds. lets find the distance 1st.
s=d/t.
let's say time taken be 1hr. so acc to this distance covered till point B is 45km
n from B to C is 54km
So, the distance gap is of 9km.

Now the time lapse for this distance we have to find. the extra distance from B to C is covered with speed of 54km/hr.
Thus, t= 9/ 54 is 1/6 hr.
So 1/6hr * 60 = 10 mins.

Thanks for the answer @Jaya.