Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = |  |
9 | x 60 |  min |
= 10 min. |
| 54 |
Discussion:
205 comments Page 12 of 21.
Sangay wangdi said:
5 years ago
54 km in 60 minutes.
9km in x.
Cross multiply.
60 * 9 =540/54.
Is equal to 10 minutes.
So, 9km is taking 10 minutes to stop.
9km in x.
Cross multiply.
60 * 9 =540/54.
Is equal to 10 minutes.
So, 9km is taking 10 minutes to stop.
SABHU said:
4 years ago
Min per hour= (difference of two speeds÷ without stoppage)*60.
Or
Min per hour=(diff of two speeds÷ large number)*60.
Or
Min per hour=(diff of two speeds÷ large number)*60.
(4)
Nitesh Nandwana said:
1 decade ago
@Girishkumar hi itz simple.
Because 54km in 1 hour.
So 1 km in 1/54 hour.
So 9 km in 9* (1/54) *60 min (1 hour = 60 min).
Because 54km in 1 hour.
So 1 km in 1/54 hour.
So 9 km in 9* (1/54) *60 min (1 hour = 60 min).
Shaju said:
1 decade ago
Hey its 54 kmph and 45 kmph. Can you explain how you got 9 km by subtracting the speeds of bus at different circumstances?
Prithvi said:
6 years ago
For 54 km it is 60 min.
For 45 km how much?
54 = 60
45 = x
X = 50, the difference in time 10 min gives us stoppage time.
For 45 km how much?
54 = 60
45 = x
X = 50, the difference in time 10 min gives us stoppage time.
Sumit Dubey said:
1 decade ago
@Dushanthi,
Is there any shortcut method for solving the same problem (Brijesh Kesharia's que. ) for more complex data?
Is there any shortcut method for solving the same problem (Brijesh Kesharia's que. ) for more complex data?
Bala said:
1 decade ago
Due to the stoppages it travelled 9km less. So
For 1 hr -> 54km.
t(hr) -> 9km.
t = 9/54 = 1/60 = 60/6 = 10min.
For 1 hr -> 54km.
t(hr) -> 9km.
t = 9/54 = 1/60 = 60/6 = 10min.
Alok kumar mishra said:
1 decade ago
54km less if it stop for 1 hr.
1km less if it stop for 1/54 hr.
9km less if it stop for 9/54 hr = 9/54*60 = 10 min.
1km less if it stop for 1/54 hr.
9km less if it stop for 9/54 hr = 9/54*60 = 10 min.
Prasanth said:
9 years ago
Take it as ratio type 45 (9 * 5) : 54 (9 * 6).
Then convert it (54) to 60mins 50 : 60.
So 60 - 50 = 10 that's it.
Then convert it (54) to 60mins 50 : 60.
So 60 - 50 = 10 that's it.
Umer said:
4 years ago
1hr distance without stoppage = 54km,
1hr distance with stoppage = 45km,
=> distance difference = 9.
9/54*60=10.
1hr distance with stoppage = 45km,
=> distance difference = 9.
9/54*60=10.
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