Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = |  |
9 | x 60 |  min |
= 10 min. |
| 54 |
Discussion:
205 comments Page 12 of 21.
Veeresh said:
1 decade ago
Why we are considering 54 kmph rather 45 kmph?
Guna said:
1 decade ago
Please explain in min to sec and min to hours.
SANDEEP said:
1 decade ago
I will suggest one more formula to solve this kind of problems when stoppage time has to be calculated.
Then, stoppage time = 1-Slower speed/Faster speed.
Hence in this case.
= 1-45/54.
= 1- 5/6.
= (6-5)/6.
= 1/6.
Which can be converted to = 1/6*60 = 10 min.
Then, stoppage time = 1-Slower speed/Faster speed.
Hence in this case.
= 1-45/54.
= 1- 5/6.
= (6-5)/6.
= 1/6.
Which can be converted to = 1/6*60 = 10 min.
Sha said:
1 decade ago
How can you take if t=1 randomly?
Aditya said:
10 years ago
There is a formula for this questions:
(V1-v2)/v1.
V1= Without stoppage velocity.
V2 = With stoppage.
Result is in hour. Multiply by 60 to get minutes.
(V1-v2)/v1.
V1= Without stoppage velocity.
V2 = With stoppage.
Result is in hour. Multiply by 60 to get minutes.
Ronak Bhatia said:
10 years ago
For 60 min......54 kmph so.
For ? min.......45 kmph.
= 45*60/54 = 50 mins it means 10 mins less so it has stopped for 10 mins.
For ? min.......45 kmph.
= 45*60/54 = 50 mins it means 10 mins less so it has stopped for 10 mins.
Just for you said:
10 years ago
We are taking 9/54, because car is moving @ 54 not 45 km/hr. The question is on average speed which means total distance divided by total time.
Now, because car waits for some minutes at stops that is why average speed gets decreased. So, speed is same which is 54 km/hr, but including stoppages total time has increased. Therefore average speed comes down.
Now, because car waits for some minutes at stops that is why average speed gets decreased. So, speed is same which is 54 km/hr, but including stoppages total time has increased. Therefore average speed comes down.
Somanka said:
10 years ago
Formula:
If a body moves at an average speed of V1 km/hr to cover a distance of D km without stopping and moves at an average speed V2 km/hr to cover the same distance.
Then stoppage time/hour is: (V1-V2) /V1.
= (54-45)/54 = 10 mins.
If a body moves at an average speed of V1 km/hr to cover a distance of D km without stopping and moves at an average speed V2 km/hr to cover the same distance.
Then stoppage time/hour is: (V1-V2) /V1.
= (54-45)/54 = 10 mins.
Deepika said:
9 years ago
Well said @Nitesh Nandwana.
It's simple and easy to solve.
It's simple and easy to solve.
Abc said:
9 years ago
Why we considered 54?
Let's do this way:
Let us consider a distance d km and the second vehicle takes x time more.
Then,
D = 54km/hr * 1hr as 54km/hr is without stoppage so it'll take.
Less time.
D = 45km/hr * (1 + x) including stoppage will take more time to.
To cover d km.
54 * 1 = 45 (1 + x).
54 - 45 = 45x.
9 = 45x.
The, x = 9/45 = 0.2hr.
=> 0.2hr = 0.2 * 60 min = 12 min.
Let's do this way:
Let us consider a distance d km and the second vehicle takes x time more.
Then,
D = 54km/hr * 1hr as 54km/hr is without stoppage so it'll take.
Less time.
D = 45km/hr * (1 + x) including stoppage will take more time to.
To cover d km.
54 * 1 = 45 (1 + x).
54 - 45 = 45x.
9 = 45x.
The, x = 9/45 = 0.2hr.
=> 0.2hr = 0.2 * 60 min = 12 min.
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