Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 5)
5.
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
Answer: Option
Explanation:
Due to stoppages, it covers 9 km less.
| Time taken to cover 9 km = |  |
9 | x 60 |  min |
= 10 min. |
| 54 |
Discussion:
206 comments Page 11 of 21.
Sumit Dubey said:
1 decade ago
@Dushanthi,
Is there any shortcut method for solving the same problem (Brijesh Kesharia's que. ) for more complex data?
Is there any shortcut method for solving the same problem (Brijesh Kesharia's que. ) for more complex data?
Ashish said:
1 decade ago
For all those who got answer as 12.
12 min is the stoppage time for (60+12) min i.e 72 min. So, for 60 min. i.e 1 hr it would be 60* 12/72=10 min.
12 min is the stoppage time for (60+12) min i.e 72 min. So, for 60 min. i.e 1 hr it would be 60* 12/72=10 min.
Alok kumar mishra said:
1 decade ago
54km less if it stop for 1 hr.
1km less if it stop for 1/54 hr.
9km less if it stop for 9/54 hr = 9/54*60 = 10 min.
1km less if it stop for 1/54 hr.
9km less if it stop for 9/54 hr = 9/54*60 = 10 min.
Bala said:
1 decade ago
Due to the stoppages it travelled 9km less. So
For 1 hr -> 54km.
t(hr) -> 9km.
t = 9/54 = 1/60 = 60/6 = 10min.
For 1 hr -> 54km.
t(hr) -> 9km.
t = 9/54 = 1/60 = 60/6 = 10min.
Arun said:
1 decade ago
Why you have taken 54 and why not 45?
ARJUN SAHOO said:
1 decade ago
See..the bus runs up to 54 kmph in 60m. in nonstop mode.
If 45km in stop mode, the bus will take 72 minutes to travel 54 km in stop mode.(60/45*54).
So here bus taking 12 more minutes to reach at the destination but in 72 minutes. As per question, in 60 minutes the bus will take extra minutes to halt => 12/72*60=10 proved. Answer is 10.
If 45km in stop mode, the bus will take 72 minutes to travel 54 km in stop mode.(60/45*54).
So here bus taking 12 more minutes to reach at the destination but in 72 minutes. As per question, in 60 minutes the bus will take extra minutes to halt => 12/72*60=10 proved. Answer is 10.
Saurabh said:
1 decade ago
For those who got i2 min as answer.
Solve like this;
As distance is same....
54=d/(1-x).........(1) where x is the stoppage time.
45=d/1.............(2).
Solving eq 1 & 2,we get x=0.166 hrs. So in minutes ANS = 10.
Solve like this;
As distance is same....
54=d/(1-x).........(1) where x is the stoppage time.
45=d/1.............(2).
Solving eq 1 & 2,we get x=0.166 hrs. So in minutes ANS = 10.
Suresh said:
1 decade ago
Excluding stoppages, the speed of a bus is 54 kmph.
Including stoppages, the speed of a bus is 45 kmph.
The difference between 54 and 45 is 9 that means the bus stopped.
Overall about 9 kms.
Formula : (Difference/Bigger value)*60.
Therefore (9/54)*60.
Including stoppages, the speed of a bus is 45 kmph.
The difference between 54 and 45 is 9 that means the bus stopped.
Overall about 9 kms.
Formula : (Difference/Bigger value)*60.
Therefore (9/54)*60.
Lipu said:
1 decade ago
If speed is 54 kmph.
So in one hour bus travels 54 km.
Again time taken by bus to travel 54 km with speed 45 kmph will be (54/45) *60 min=72 min.
So to reach at the same position more time required 12 min.
So 12 min is the stopped time.
So in one hour bus travels 54 km.
Again time taken by bus to travel 54 km with speed 45 kmph will be (54/45) *60 min=72 min.
So to reach at the same position more time required 12 min.
So 12 min is the stopped time.
Deba said:
1 decade ago
Why we are considering 54 kmph rather 45 kmph?
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