Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
350 comments Page 9 of 35.
Sushil said:
1 decade ago
Let the car speed is x kmph
ie,the car speed is 100x kmph
Then train speed is 150kmph
equation is 75/1.5x+12.5/60=75/x
x=120kmph
ie,the car speed is 100x kmph
Then train speed is 150kmph
equation is 75/1.5x+12.5/60=75/x
x=120kmph
Faizan Akhtar said:
1 decade ago
75/x - 75/3x/2 = 125/10*60
can you tell me how this equations is derived?
can you tell me how this equations is derived?
Deepak porwal said:
1 decade ago
As the train speed is 50% more than car
So train speed is (car speed + 50% of car speed)
i.e. (x+(50/100)*x)= 3x/2;
now time diffrence between them is 12.5 minute
converting it in to hour 12.5/60;
now (distance/speed of train) - (distance /speed of car)= 12.5/60;
as time diffrence between them is 12.5 min;
So train speed is (car speed + 50% of car speed)
i.e. (x+(50/100)*x)= 3x/2;
now time diffrence between them is 12.5 minute
converting it in to hour 12.5/60;
now (distance/speed of train) - (distance /speed of car)= 12.5/60;
as time diffrence between them is 12.5 min;
Pradeep said:
1 decade ago
Can you exlpain how 150x/100 came ?
Rohita said:
1 decade ago
Explain the simple way, I can't understand train speed.
Senhil said:
1 decade ago
Given train is 50% greater than car. Let car speed will be 50km/hr then train speed ll be 100km/hr. So 100+50=150 km/hr.
Prasad said:
1 decade ago
Train speed is 50% more than car, so it is 1/2 % more speed than car .
So it is 1 and 1/2 == 3/2 ( as car 100% it will be 1).
So it is 1 and 1/2 == 3/2 ( as car 100% it will be 1).
Jamal akhter said:
1 decade ago
Could you explain how time for train you had taken 75/(3/2.x) ?
Suja said:
1 decade ago
@ jamal:
We know that time=(distance/speed).
Here distance=75kmph and speed=3x/2.
Therefore time=75/(3x/2)
We know that time=(distance/speed).
Here distance=75kmph and speed=3x/2.
Therefore time=75/(3x/2)
Shunmuga priya said:
1 decade ago
Sonam Jain said that " (125/10*60)it takes the difference b/w boths time is equal to the lost time "
But in question it is clearly given as "from point A at the same time and reach point B 75 kms away from A at the same time". The car and train starting and ending time is same so no need of subtraction but they subtracted here.
I cant get this. please explain
But in question it is clearly given as "from point A at the same time and reach point B 75 kms away from A at the same time". The car and train starting and ending time is same so no need of subtraction but they subtracted here.
I cant get this. please explain
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