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Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 4)
Time and Distance
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
100 kmph
110 kmph
120 kmph
130 kmph
Answer: Option
Explanation:

Let speed of the car be x kmph.

Then, speed of the train = 150 x = 3 x kmph.
100 2

75 - 75 = 125
x (3/2)x 10 x 60

75 - 50 = 5
x x 24

x = 25 x24 = 120 kmph.
5

Discussion:
345 comments Page 9 of 35.
Naga sai said:   5 years ago
@Rishika.

We are subtracting it because the time difference between them is 12.5 min.
Rishika said:   5 years ago
Why are we subtracting 75/x - 75/3/2x? Please explain.
Anjali said:   5 years ago
How 125/10 * 60 come at the initial step? Please explain.
Jen said:   5 years ago
Thanks all.
Adla said:   5 years ago
Car speed is x.

Speed of train = 150/100x= 3/2xkmph(explain 25*3/25*2).
75/x-75/3/2x = 12.5/60.
75/x-75/3/2x = 125/600.
75/x-75*2/3x = 5/24.
75/x-150/3x = 5/24.
75/x-50/x = 5/24.
25/x = 5/24.
x= 25*24/5.
x= 5*24.
x= 120.
Kalyan said:   5 years ago
Can you explain how 150/100 came?
Sravani said:   5 years ago
Why to subtract the speed of the train from speed of car (75/x-75x/[3/2])?

Can anyone help me by explaining?
(1)
Rezviii said:   5 years ago
Why dividing 125 by 10* 60?

Please explain it.
Surya said:   5 years ago
75/x - 75/(3/2) =125/10*60.
Anyone can explain this?

How this 125/10*60 came?
Rohith said:   5 years ago
Can someone give a clear explanation for this problem?
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