Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
350 comments Page 8 of 35.
Sahil Tiwari said:
5 years ago
Speed = D/T.
i.e- 75/12.5 = 60km.
The speed is 50% more;
60 is 50% of 120 = 120 kmph.
i.e- 75/12.5 = 60km.
The speed is 50% more;
60 is 50% of 120 = 120 kmph.
(3)
Anonymous said:
5 years ago
@VIcky045.
Actually,
To take delay time of train we need to have express time in hr(given is in min).
To convert Minute to Hour (x minutes/60).
To convert Hour to Minute (x hours*60).
So,
Converting 12.5 mins to 12.5/60 hour.
125/10*60 also correct since it only removes decimals.
Actually,
To take delay time of train we need to have express time in hr(given is in min).
To convert Minute to Hour (x minutes/60).
To convert Hour to Minute (x hours*60).
So,
Converting 12.5 mins to 12.5/60 hour.
125/10*60 also correct since it only removes decimals.
Vicky045 said:
5 years ago
By Change Minute to hours 12.5*60.
Am I right, then how 12.5/60? Please explain me.
Am I right, then how 12.5/60? Please explain me.
XiYoZ said:
5 years ago
How (24 *25)/5 came?
Aldrin said:
5 years ago
Also, they assumed that the car didn't stop anywhere and was continuously travelling.
Navas said:
5 years ago
I'm not getting your answer method, please explain to me in detail.
Hani said:
5 years ago
@Shavra Yaqub Shah.
I'm not getting your answer method, please explain to me in detail.
I'm not getting your answer method, please explain to me in detail.
Shavra yaqub shah said:
5 years ago
T1 - T2 = 12.5 minutes
speed1/distance1 - speed2/distance2 = 12.5 minutes .
@All.
This is how you form the equation and solve the problem related to the time difference (early/late than usual),or speed difference or distance difference.
speed1/distance1 - speed2/distance2 = 12.5 minutes .
@All.
This is how you form the equation and solve the problem related to the time difference (early/late than usual),or speed difference or distance difference.
Jay said:
5 years ago
How 3/2 come? Please explain.
Priyam said:
5 years ago
@Aditya Mohanty.
For converting the minute into the hour we take 12.5/60 and when we remove the decimal point it became 125/60*10.
For converting the minute into the hour we take 12.5/60 and when we remove the decimal point it became 125/60*10.
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