Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
342 comments Page 6 of 35.
Raihan Bangladesh said:
8 years ago
Let, car speed = X km/min.
Train speed = X + x* (50/100) Km/min.
=X+X/2 km/min.
=3X/2 km/min.
Time of car t =75/X.
Time of Train t =75/ (3X/2).
According to the question.
75/X=75/ (3X/2) +12. 5.
>> 75/X-150/3X=12. 5.
>> (225-150) /3X=12. 5.
>> 75 = 37. 5X.
>> X = 2 Km/min.
So car speed 1 minute to 2 km.
Car Speed 60 minutes to (60*2) = 120 km/h.
Train speed = X + x* (50/100) Km/min.
=X+X/2 km/min.
=3X/2 km/min.
Time of car t =75/X.
Time of Train t =75/ (3X/2).
According to the question.
75/X=75/ (3X/2) +12. 5.
>> 75/X-150/3X=12. 5.
>> (225-150) /3X=12. 5.
>> 75 = 37. 5X.
>> X = 2 Km/min.
So car speed 1 minute to 2 km.
Car Speed 60 minutes to (60*2) = 120 km/h.
(1)
Sravani said:
5 years ago
Why to subtract the speed of the train from speed of car (75/x-75x/[3/2])?
Can anyone help me by explaining?
Can anyone help me by explaining?
(1)
Arvind Gupta said:
5 years ago
Late Train speed = X km/hrs.
Than Car speed will be = X+X/2 =3X/2 km/hrs,
Time_train - Time_car = Time - train stop.
75/X - 75/(3/2)X = 12.5/60,
75/X - 50/X = 25/120,
25/X = 25/120.
X = 120 km/hrs Ans.
Than Car speed will be = X+X/2 =3X/2 km/hrs,
Time_train - Time_car = Time - train stop.
75/X - 75/(3/2)X = 12.5/60,
75/X - 50/X = 25/120,
25/X = 25/120.
X = 120 km/hrs Ans.
(1)
PALAK said:
4 years ago
Let the car speed be x.
Speed of train = 150/100x = 3/2xkmph(explain 25*3/25*2).
75/x-75/3/2x = 12.5/60.
75/x-75/3/2x = 125/600.
75/x-75*2/3x = 5/24.
75/x-150/3x = 5/24.
75/x-50/x = 5/24.
25/x = 5/24.
x = 25*24/5.
x = 5*24.
x = 120.
Speed of train = 150/100x = 3/2xkmph(explain 25*3/25*2).
75/x-75/3/2x = 12.5/60.
75/x-75/3/2x = 125/600.
75/x-75*2/3x = 5/24.
75/x-150/3x = 5/24.
75/x-50/x = 5/24.
25/x = 5/24.
x = 25*24/5.
x = 5*24.
x = 120.
(1)
Yogi said:
4 years ago
@Yogi,
Train increase speed 1/2, means time decrease 1/3,
This 1/3 =12.5 minute. = 12.5/60 = 5/24 hour,
Speed = distance/time.
Speed(train)= 75km/5/24 = 360km/h,
Car speed = train speed/2,
Car speed =120kmph.
Train increase speed 1/2, means time decrease 1/3,
This 1/3 =12.5 minute. = 12.5/60 = 5/24 hour,
Speed = distance/time.
Speed(train)= 75km/5/24 = 360km/h,
Car speed = train speed/2,
Car speed =120kmph.
(1)
Yogi said:
4 years ago
The Speed of train increase by 1/2, means time reduce by 1/3, this 1/3 time reduction is 12.5 minute.
So, 1/3 = 12.5/37.5.
Means the car will take three-time of 12.5 minutes which 37.5 minutes.
75 x 60/37.5 = 120kmph.
So, 1/3 = 12.5/37.5.
Means the car will take three-time of 12.5 minutes which 37.5 minutes.
75 x 60/37.5 = 120kmph.
(1)
Shubham said:
4 years ago
It's given that both Car and the train covers 75kms at the same time (t1=t2)
t=d/s
Let's assume car speed as 'x' km/hr.
Train Speed = x + x/2.
=3/2x.
t1=75/x.
t2=75/(3/2)*x.
t1 = t2+12.5mins extra time.
Then solve by converting 12.5 mins to hr by dividing by 60.
t=d/s
Let's assume car speed as 'x' km/hr.
Train Speed = x + x/2.
=3/2x.
t1=75/x.
t2=75/(3/2)*x.
t1 = t2+12.5mins extra time.
Then solve by converting 12.5 mins to hr by dividing by 60.
(1)
Vidhyasaagar said:
4 years ago
@All.
The soultion is;
Speed of car = x =>1x=>100/100x.
(All are literally same, in terms of percentage it's 100/100x).
Speed of train = 50%+ x=> (50/100)+(100/100x)=150/100x=3/2x.
The soultion is;
Speed of car = x =>1x=>100/100x.
(All are literally same, in terms of percentage it's 100/100x).
Speed of train = 50%+ x=> (50/100)+(100/100x)=150/100x=3/2x.
(1)
Tharun kumar said:
3 years ago
Let the speed of the car be x.
As per the data the train is 50% faster than a car (not 50 times) which means [ (50/100) x +x].
So, (150/100) x.
As per the data the train is 50% faster than a car (not 50 times) which means [ (50/100) x +x].
So, (150/100) x.
(1)
Chandra mouli said:
2 decades ago
Let car speed be xkmph
then train speed is 50% more than car speed
ie 50/100*x
then train speed is 50% more than car speed
ie 50/100*x
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