Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
100 kmph
110 kmph
120 kmph
130 kmph
Answer: Option
Explanation:

Let speed of the car be x kmph.

Then, speed of the train = 150 x = 3 x kmph.
100 2

75 - 75 = 125
x (3/2)x 10 x 60

75 - 50 = 5
x x 24

x = 25 x24 = 120 kmph.
5

Discussion:
355 comments Page 4 of 36.

Charles said:   4 years ago
I did not understand. Please help me to get it.
(17)

SHREYA said:   9 months ago
The speed of the car is x km/h.
The speed of the train = x + 50x/100,
= 150x/100,
= 3x/2 km/h.

The time taken by the car = 75/x.
The time taken by the train = 75/(3x/2).

The difference between them is 12.5 minutes.
75/x - 75/(3x/2) = 12.5 minutes.

To convert minutes to hours, divide the number by 60,
Therefore,
75/x - 75/(3x/2) = 12.5/60 hr,
75/x - 75/(3x/2) = 125/(10*60) hr,
75/x - 50/x = 5/24,
25/x = 5/24,
5x = 25*24.
x = 120 km/hr.
(17)

Bhushan said:   4 years ago
Let the speed of car be x.
now, the train is 50% faster than a car,
i.e. speed of the train = x + (50/100)x.
= 150x/100.
(16)

Kishorebabu said:   2 years ago
Convert km/h to m/s.

S(c) = 75000/T -->(1)
S(tr) = 75000/(T-12.5x60)-->(2)
S(tr) = 3/2S(c) -->(3)

Sub (3) in (2).
3/2s(c) = 75000/(T-12.5x60).

sub (1) in above;

(3/2).(75000/T) = 75000/(T-12.5x60).
T = 3x12.5x60 ---->(4)

Sub (4 in (1) [to get the speed of the car].
S(c) = (75000/3x12.5x60 ).(18/5).
s(c) = 120km/h.
(16)

Anu said:   9 months ago
Most of people saying 1/2 instead of 3/2 is wrong.

The train is 50% more means 1/2 and also 1 for the car speed is added, So it's 3/2.
(15)

Sai Durga said:   3 years ago
Let the speed of the train be x.

So, train speed 50% faster than car means x + x/2 = 3x/2, speed = 75km/hr,
Time delayed = 12.5 mins = 12.5/60 sec.
Now;
D/s = T; (here speed = speed of the car -speed of the train),
So,
75/x -75/3x/2 = 12.5/60.
75/x - 50/x = 5/24.
x = 25 x 24/5.
x = 120 km/hr.
(13)

Saloni Adhikari said:   3 years ago
Here, How can we say given time in the question is equal to the value obtained after subtraction? Please explain me.
(13)

Siddardha said:   3 months ago
@ALL.

Time, distance, and speed problems always assume one variable as constant and calculate the others.
See in this question, started at A and reached at B (75 km).

Both the car and the train reached point B at the same time, even though their speeds are not the same, because the train had waited 12.5 mins in between. So the train has travelled 12.5 minutes less than the total time taken by car.
So, the difference in their times is just 12.5 mins.
t1 - t2 = 12.5 mins (t=d/s)
d1/s1 - d2/s2 = 12.5 mins. ( let x is speed of the car, and 50% more will be 1.5x )
75/x - 75/(1.5x) = 12.5/60 hr.

Solve this as it has only 1 unknown, we will get the speed of the car.
(13)

Renny said:   1 year ago
Thanks for explaining the answer @VIJETH BK.
(11)

Abhishek S k said:   10 months ago
I didn't understand this, anyone please explain to me?
(11)


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