Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
100 kmph
110 kmph
120 kmph
130 kmph
Answer: Option
Explanation:

Let speed of the car be x kmph.

Then, speed of the train = 150 x = 3 x kmph.
100 2

75 - 75 = 125
x (3/2)x 10 x 60

75 - 50 = 5
x x 24

x = 25 x24 = 120 kmph.
5

Discussion:
345 comments Page 24 of 35.

Ershaad shah said:   7 years ago
@Trishita.

Can you please explain, how do you put 75/100x-75/150x = 125/600?

Xyz said:   2 decades ago
When we take 50x/100

we get x=[-75* 24]/5 = - 360kmph
its not in the option

Tanshi said:   9 years ago
The formula to convert from minutes to hours is:
hours = minutes ÷ 60.

Rakesk said:   2 decades ago
50 % more means not 50/100. car has already 100 %.50 % more means 150/100
(2)

Faizan Akhtar said:   1 decade ago
75/x - 75/3x/2 = 125/10*60
can you tell me how this equations is derived?

Chinna said:   7 years ago
Here why we used 75/x-75/(3/2)x=125/10*60.
Please anyone can explain me?.

Raul said:   1 decade ago
100*(t)=150*(t+12.5)
t=37.5min
t
=37.5/60hr
speed=(75*60)/37.5
=120

Jarvis said:   6 years ago
If it's 50x.

It says that train travels in 50% less speed than the car.

Sandy said:   1 decade ago
Please any one can explain the equation [75/x]-[75/1.5x] = [12.5/60].

VIJAY said:   6 years ago
Here, we can use Car travel time = train travel time + stoppage time.


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