Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
350 comments Page 23 of 35.
Hani said:
5 years ago
@Shavra Yaqub Shah.
I'm not getting your answer method, please explain to me in detail.
I'm not getting your answer method, please explain to me in detail.
Somya said:
1 decade ago
@Neo, your method is good. I just want to know how you got that 32.5? please elaborate?
Naga sai said:
5 years ago
@Rishika.
We are subtracting it because the time difference between them is 12.5 min.
We are subtracting it because the time difference between them is 12.5 min.
Aldrin said:
5 years ago
Also, they assumed that the car didn't stop anywhere and was continuously travelling.
Sahil Tiwari said:
5 years ago
Speed = D/T.
i.e- 75/12.5 = 60km.
The speed is 50% more;
60 is 50% of 120 = 120 kmph.
i.e- 75/12.5 = 60km.
The speed is 50% more;
60 is 50% of 120 = 120 kmph.
(3)
Sandeep said:
1 decade ago
Let as take car speed as =100 than train speed is 50% faster than car so 100+50=150.
Vicky045 said:
5 years ago
By Change Minute to hours 12.5*60.
Am I right, then how 12.5/60? Please explain me.
Am I right, then how 12.5/60? Please explain me.
Deepana M said:
1 month ago
The train can travel 50% faster than a car. How to define 150 here? Please explain.
(3)
Chandra mouli said:
2 decades ago
Let car speed be xkmph
then train speed is 50% more than car speed
ie 50/100*x
then train speed is 50% more than car speed
ie 50/100*x
Nahid said:
5 years ago
Let,
Speed of the car= x kph.
So, speed of the train = x + 50% of x = (3x/2) kph.
Speed of the car= x kph.
So, speed of the train = x + 50% of x = (3x/2) kph.
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