Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
342 comments Page 24 of 35.
GIS said:
1 decade ago
Let Speed of Car = x.
Train is 50% faster than car = x + x/2 = 3x/2.
Time difference = 12. 5 mins = 12. 5/60 hours = 125/600 = 5/24.
Distance = 75 km.
(Distance/Car speed) - (Distance/Train speed) = 12. 5 min = 5/24 hr.
(75/x) - (75/ (3/2x) ) = 5/24.
(75/x) - (150/3x) = 5/24.
25/x = 5/24.
X = (25*24) /5 = 120kmph.
Train is 50% faster than car = x + x/2 = 3x/2.
Time difference = 12. 5 mins = 12. 5/60 hours = 125/600 = 5/24.
Distance = 75 km.
(Distance/Car speed) - (Distance/Train speed) = 12. 5 min = 5/24 hr.
(75/x) - (75/ (3/2x) ) = 5/24.
(75/x) - (150/3x) = 5/24.
25/x = 5/24.
X = (25*24) /5 = 120kmph.
Prasad chowdary said:
1 decade ago
Hi, @Arun to remove the decimal form 12.5. We multiply and divide 10.
(12.5*10)/10 = 125/10.
(12.5*10)/10 = 125/10.
Arun sanap said:
1 decade ago
Hey. I can't get how they take 125/10*60. In that I understand 125/60 but. How they take 10? Please help me.
Manu said:
1 decade ago
50% more than the car speed means lets car speed is 100 usual assumption 50% more means 150%.
Sriram Kalyan said:
1 decade ago
Can you please explain the first step. How did you take 150x/100?
Jothi said:
1 decade ago
What you mean by percentage ? hey its not the additional value to add with existent one number. How its possible to 3/2 for 50% ? 1/2 is only possible for 50%.
Ramesh said:
1 decade ago
Why the LHS is equated with RHS?
Anonymous said:
1 decade ago
Let the speed of the car be x.
Then 50 percent of x = x/2.
Speed of the train = x + x/2 = 3x/2.
Then 50 percent of x = x/2.
Speed of the train = x + x/2 = 3x/2.
Mudassir said:
1 decade ago
Hi,
S=D/T
D=75, T=?, S=?
We need to find out the Time T, to get the speed S.
Time difference given as 12.5 mins, within 12.5 mins car is able to cover the same distance as train.
If the speed of the car be 100, then the train speed be 150.
It means 12.5 minus = 1/3 km.
12.5=75/3=25.
Therefore in 12.5 mins distance covered is 25km.
Here distance is given in km.
Therefore convert 12.5 minutes to hour i.e., 12.5/60=0.20833.
0.20833 hr = 25 km.
? = 75 km.
By cross multiplication the time taken to reach 75 km is 0.6249.
.
. . s = d/t.
s = 75/0.6249 = 120km.
S=D/T
D=75, T=?, S=?
We need to find out the Time T, to get the speed S.
Time difference given as 12.5 mins, within 12.5 mins car is able to cover the same distance as train.
If the speed of the car be 100, then the train speed be 150.
It means 12.5 minus = 1/3 km.
12.5=75/3=25.
Therefore in 12.5 mins distance covered is 25km.
Here distance is given in km.
Therefore convert 12.5 minutes to hour i.e., 12.5/60=0.20833.
0.20833 hr = 25 km.
? = 75 km.
By cross multiplication the time taken to reach 75 km is 0.6249.
.
. . s = d/t.
s = 75/0.6249 = 120km.
Sadhana said:
1 decade ago
Hi,
Why 150/100 why not 100/150?
Why 150/100 why not 100/150?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers