Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
353 comments Page 23 of 36.
Mukund said:
1 decade ago
I think the question is technically wrong. It is given that both the car & train reach point B at the same time.
Then what is the significance of lagging of train by 12.5 min. And if it is so (if they reach in same time) then the equation this should be valid.
75/x = 75/x+ (x/2).
Where x = Speed of car.
x+(x/2) = Speed of train.
Then what is the significance of lagging of train by 12.5 min. And if it is so (if they reach in same time) then the equation this should be valid.
75/x = 75/x+ (x/2).
Where x = Speed of car.
x+(x/2) = Speed of train.
Fazil said:
1 decade ago
Can't we say speed of train is 50% faster than car.
If speed of car is x, then train must move with 2x speed. Is it?
If speed of car is x, then train must move with 2x speed. Is it?
Rohit said:
1 decade ago
Let speed of car be = x km/hr.
Then, speed of train will be = 50% more than car.
50% means half of speed of car.
Half of car speed can be written as "x/2.
Then, speed of train will be = x+x/2 = 3x/2.
Total distance = 75km.
Then, according to question Time = Distance/Speed,
75/3x/2-75/x = 12.5.
300/3x-75/x = 125/10/60.
300-225/3x = 125/600.
75/3x = 5/24.
3x*5 = 75*24.
3x = 75*24/5.
Therefore, x = 75*24/15.
x = 5*24 = 120.
Then, speed of train will be = 50% more than car.
50% means half of speed of car.
Half of car speed can be written as "x/2.
Then, speed of train will be = x+x/2 = 3x/2.
Total distance = 75km.
Then, according to question Time = Distance/Speed,
75/3x/2-75/x = 12.5.
300/3x-75/x = 125/10/60.
300-225/3x = 125/600.
75/3x = 5/24.
3x*5 = 75*24.
3x = 75*24/5.
Therefore, x = 75*24/15.
x = 5*24 = 120.
Deepak said:
1 decade ago
Please explain in easy way can't understand please.
Sowmiya.k said:
1 decade ago
Please anybody explain it briefly I can't understand.
Satyajit said:
1 decade ago
Train is faster so it should have been 75/(3/2*x)-75/x = 125/10*60.
Bhu said:
1 decade ago
Time of train+12.5 = Time of car.
Sarath said:
1 decade ago
In one way it can be understood as difference of times is 12.5 min.
i.e 75/x-50/x = 12.5 min.
But, if the time taken by train is excess 12.5 mins then car reaches before 12.5 mins.
We write this as car time + 12.5 mins excess = Train time i.e 75/x+ 12.5 min = 50/x.
i.e 75/x-50/x = 12.5 min.
But, if the time taken by train is excess 12.5 mins then car reaches before 12.5 mins.
We write this as car time + 12.5 mins excess = Train time i.e 75/x+ 12.5 min = 50/x.
Gourav said:
1 decade ago
How to solve this question please tell me right formulas?
Tarun said:
1 decade ago
Lost time is equal to difference between the time taken by car in X kmph and time taken by train in 150/100X kmph distance is same for both 75 kms.
= 75/X-75/(150/100)X = 12.5/60.X = 120 kmph.
= 75/X-75/(150/100)X = 12.5/60.X = 120 kmph.
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