Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
345 comments Page 18 of 35.
Kulwant said:
1 decade ago
Simple:
Total Distance is 75kms.
Both train and car reached at same time in-spite of train having speed advantage of 50% over car i.e. 3/2.
Train lost this advantage due to 12.5 minutes stoppage.
That means this 12.5 minutes lost time equals to the speed advantage of train, had it not lost this time train would have reached earlier.
Therefore 12.5 *3 = 37.5 is the time taken by car to cover 75 kms.
Train took similar time to cover 75 distance stopping for 12.5 minutes. Had it not stopped it would have covered in 25 minutes (37.5-12.5 = 25).
S=d/t : Speed of car = 75/37.5 = 2 km per hour 2*60 = 120 km per hour.
Total Distance is 75kms.
Both train and car reached at same time in-spite of train having speed advantage of 50% over car i.e. 3/2.
Train lost this advantage due to 12.5 minutes stoppage.
That means this 12.5 minutes lost time equals to the speed advantage of train, had it not lost this time train would have reached earlier.
Therefore 12.5 *3 = 37.5 is the time taken by car to cover 75 kms.
Train took similar time to cover 75 distance stopping for 12.5 minutes. Had it not stopped it would have covered in 25 minutes (37.5-12.5 = 25).
S=d/t : Speed of car = 75/37.5 = 2 km per hour 2*60 = 120 km per hour.
Kamesh said:
1 decade ago
I don't understand this problem please solve easily.
Diwakar.I said:
1 decade ago
Can anyone explain how(150/100) came?
ANAND said:
1 decade ago
50% car faster means 100%+50% = 150.
Pramod said:
1 decade ago
50% faster means 1+1/2 = 3/2.
Ashish said:
1 decade ago
50% more than x means 50/100 + x = 150/100x.
Gourav said:
1 decade ago
How to solve this question please tell me right formulas?
Tarun said:
1 decade ago
Lost time is equal to difference between the time taken by car in X kmph and time taken by train in 150/100X kmph distance is same for both 75 kms.
= 75/X-75/(150/100)X = 12.5/60.X = 120 kmph.
= 75/X-75/(150/100)X = 12.5/60.X = 120 kmph.
Tarun said:
1 decade ago
Its easy guys OK I explain. Let speed of car is X.
Then speed of train is 150/100 multiply by X. Then after solve this 3/2X kmph.
Taking difference between car and train speed minutes.
= 75/x-75/3/2x = 12.5/60. Then speed of car means X is equal to 120 kmph.
Then speed of train is 150/100 multiply by X. Then after solve this 3/2X kmph.
Taking difference between car and train speed minutes.
= 75/x-75/3/2x = 12.5/60. Then speed of car means X is equal to 120 kmph.
Sarath said:
1 decade ago
In one way it can be understood as difference of times is 12.5 min.
i.e 75/x-50/x = 12.5 min.
But, if the time taken by train is excess 12.5 mins then car reaches before 12.5 mins.
We write this as car time + 12.5 mins excess = Train time i.e 75/x+ 12.5 min = 50/x.
i.e 75/x-50/x = 12.5 min.
But, if the time taken by train is excess 12.5 mins then car reaches before 12.5 mins.
We write this as car time + 12.5 mins excess = Train time i.e 75/x+ 12.5 min = 50/x.
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