Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
345 comments Page 12 of 35.
Amit said:
1 decade ago
Sarvya Kanchna is right:-)
dont consider x with 100 consider with 50 like this.
=x+50x/100
=(100x+50x)/100
=150x/100
If you consider x with 100 then when we take LCM then eq.
=(100x^2+50)/100x
:-)
dont consider x with 100 consider with 50 like this.
=x+50x/100
=(100x+50x)/100
=150x/100
If you consider x with 100 then when we take LCM then eq.
=(100x^2+50)/100x
:-)
Dhruva & hitesh said:
1 decade ago
First we assume that the speed of car is 100% so as per Q.speed of train is 150%.
Ajit said:
1 decade ago
In given problem ,u ve to equate total or exact time of both...
Let t be time tkn by car to cover 75kms... n t' be time takn by train...
i.e. train's total time=stoppage time+time in which it covers 75kms...nw t=t'....
Let t be time tkn by car to cover 75kms... n t' be time takn by train...
i.e. train's total time=stoppage time+time in which it covers 75kms...nw t=t'....
Santhosh said:
1 decade ago
Here,in this problem if we take 50/100 then it becomes 1/2
So we have to take 50% more..
So,assuming car speed is 100 %,then increase it to 50%..means 100+50/100 = 150/100
So we have to take 50% more..
So,assuming car speed is 100 %,then increase it to 50%..means 100+50/100 = 150/100
SONAI SHEIKH said:
1 decade ago
Why 10 is multiplied with 12.5? Can anybody explain?
Solanki said:
1 decade ago
A is faster than B by 50 percent means, take a is 100 percent and more 20 percent faster than 100+20=120. And take B is 100 percent. Then 150/100.
Nagesh said:
1 decade ago
How we get 125/10*60?
Can any one explain easy way?
Can any one explain easy way?
Ranjeet said:
1 decade ago
Let suppose car speed = x km/h
As per problem train speed 50% more than car so = x+50/100x = 3/2x.
As per problem train speed 50% more than car so = x+50/100x = 3/2x.
Firoz Rahman said:
1 decade ago
The Train lost 12.5 min to reach the destination.By this we understood that train took more time than car to reach the destination. So the car time should be subtracted from train's time and the result we get is -120. As speed will not be negative, the answer is 120. Is this right one?
Shro said:
1 decade ago
Thanks Santhiraju :).
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