Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 4)
4.
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option
Explanation:
Let speed of the car be x kmph.
| Then, speed of the train = | 150 | x | = |  |
3 | x |  kmph. |
| 100 | 2 |
 |
75 | - | 75 | = | 125 |
| x | (3/2)x | 10 x 60 |
 |
75 | - | 50 | = | 5 |
| x | x | 24 |
| x = |
|
25 x24 | |
= 120 kmph. |
| 5 |
Discussion:
345 comments Page 11 of 35.
Anas said:
6 years ago
Both trains start at the same time and reach the destination at the same time. So the time taken by both trains should be the same right? So the difference between the times should be zero. How come it is 125/10*60?
Sandhya said:
6 years ago
Can you explain 125/10*60 how it got or is there any simple method for answering this question.
Jasmine said:
6 years ago
Distance between A and B = 75kms.
Let 'x' be the speed of the car.
Given that the train can travel 50% faster than the car i.e.,
Car speed = x.
Train speed = x+x*50/100 = 3/2*x.
Distance = speed*time.
Tc(Time of the car) = 75/x.
Tt(Time of the train) = 75/(3/2*x)+12.5 min(while stopping at the station).
=>75/(3/2*x)+12.5/60(into hours).
=>75/x=75/(3/2*x)+12.5/60.
By solving x = 120kmph.
Let 'x' be the speed of the car.
Given that the train can travel 50% faster than the car i.e.,
Car speed = x.
Train speed = x+x*50/100 = 3/2*x.
Distance = speed*time.
Tc(Time of the car) = 75/x.
Tt(Time of the train) = 75/(3/2*x)+12.5 min(while stopping at the station).
=>75/(3/2*x)+12.5/60(into hours).
=>75/x=75/(3/2*x)+12.5/60.
By solving x = 120kmph.
Anandhu said:
6 years ago
Can anybody tell me that, In the question, it states that the car and the train start at the same time from A and reach at the same time a B. Which means they took the same time to reach point B from A, so how can we take the difference of time taken by them?
Anomie said:
6 years ago
Let the car speed be x.
50% of car speed =50/100*x = x/2.
The train speed = x+x/2 = 3x/2.
50% of car speed =50/100*x = x/2.
The train speed = x+x/2 = 3x/2.
Sharada said:
6 years ago
How can you get that 150/100? please explain that.
Aishwarya said:
6 years ago
Let the Speed of car be=x km/hr.
Speed of train = 1.5x km/hr.
Time taken by car to travel 75km = 75/x h.
Time taken by train to travel 75 km = 75/1.5 x-12.5/60.
Both are equal.
75/x = 75/1.5x-12.5/60.
1/x(75"75/1.5) = 12.5/60.
25/x = 12.5/60
1500 = 12.5x.
So, x = 1500/12.5 = 120 km/hr is the Answer.
Speed of train = 1.5x km/hr.
Time taken by car to travel 75km = 75/x h.
Time taken by train to travel 75 km = 75/1.5 x-12.5/60.
Both are equal.
75/x = 75/1.5x-12.5/60.
1/x(75"75/1.5) = 12.5/60.
25/x = 12.5/60
1500 = 12.5x.
So, x = 1500/12.5 = 120 km/hr is the Answer.
Shashidhar said:
6 years ago
Given.
Time delay by 12.5 (minutes),
1hr = 60minutes,
1min = (1/60)hr, 125/10 = 12.5.
125/(10*60) = (5/24).
Time delay by 12.5 (minutes),
1hr = 60minutes,
1min = (1/60)hr, 125/10 = 12.5.
125/(10*60) = (5/24).
VIJAY said:
6 years ago
Here, we can use Car travel time = train travel time + stoppage time.
Helip said:
6 years ago
If we have to convert the minute in the second we will multiply with 60 then what does it mean in solution 125/10*60? Please tell me.
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