Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 12)
12.
Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?
Answer: Option
Explanation:
Let the distance travelled by x km.
| Then, | x | - | x | = 2 |
| 10 | 15 |
3x - 2x = 60
x = 60 km.
| Time taken to travel 60 km at 10 km/hr = |  |
60 |  hrs |
= 6 hrs. |
| 10 |
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
 Required speed = |
|
60 | kmph. |
= 12 kmph. |
| 5 |
Discussion:
93 comments Page 8 of 10.
Vani said:
6 years ago
@Bhushan suriya.
How 5 hours will get at the last at 1:00pm?
How 5 hours will get at the last at 1:00pm?
Marco said:
10 years ago
The average speed :
2*10*15/10 + 15.
= 300/25.
= 12 km/h.
2*10*15/10 + 15.
= 300/25.
= 12 km/h.
Naveen said:
9 years ago
Can anyone explain in easy way? It is hard to understand.
Das said:
2 decades ago
Hi, could u tell me why we have done 60/5 in last step ?
Kuru said:
1 decade ago
@Amir that was nice, and easy step to solve.
Thanks.
Thanks.
Noorandeous said:
6 years ago
6 hours before 2 PM was not given how you added it?
TEJU said:
1 decade ago
Can any one give me the clear explanation? please.
K.NAVEENA said:
9 years ago
2xy/(x + y) = [(2 * 10 * 15)/(10 + 15)] = 12kmph.
Anushree Kulkarni said:
3 years ago
@Farzana.
Best and neat explanation, Thank you.
Best and neat explanation, Thank you.
(7)
Mano said:
1 decade ago
I agree to vishu comment. How that step came ?
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