Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 12)
12.
Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?
Answer: Option
Explanation:
Let the distance travelled by x km.
| Then, | x | - | x | = 2 |
| 10 | 15 |
3x - 2x = 60
x = 60 km.
| Time taken to travel 60 km at 10 km/hr = |  |
60 |  hrs |
= 6 hrs. |
| 10 |
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
 Required speed = |
|
60 | kmph. |
= 12 kmph. |
| 5 |
Discussion:
93 comments Page 9 of 10.
Abhi said:
7 years ago
How 60/5 comes, does any one please tell me?
Revant said:
5 years ago
Clear solution. Thank you so much @Ankit.
Ranjith said:
8 years ago
How you are saying starting 8am @Ashish.
Xyz said:
2 decades ago
Its 2 hours
12 noon to 2pm = 2 hours
12 noon to 2pm = 2 hours
Rabin said:
1 year ago
Thanks for the explanation @Farzana.
(4)
Sidhu said:
1 decade ago
It can be solve by using 2xy/x+y.
Santhosh said:
1 decade ago
How to solve the equation first?
Bharat said:
1 decade ago
x/10-x/15=2. How did 60 comes?
Ram sai said:
6 years ago
Thanks for the answer @Ashish.
Subash said:
7 years ago
Thanks for the answer @Raja.
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