Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 12)
12.
Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?
Answer: Option
Explanation:
Let the distance travelled by x km.
| Then, | x | - | x | = 2 |
| 10 | 15 |
3x - 2x = 60
x = 60 km.
| Time taken to travel 60 km at 10 km/hr = |  |
60 |  hrs |
= 6 hrs. |
| 10 |
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
 Required speed = |
|
60 | kmph. |
= 12 kmph. |
| 5 |
Discussion:
93 comments Page 7 of 10.
Neha said:
9 years ago
We can solve this problem by using avg.speed 2xy/x+y.
2 * (10 + 15)/10 + 15,
=12 km/h.
2 * (10 + 15)/10 + 15,
=12 km/h.
Arunkumar said:
2 decades ago
How to find that 2. We don't know the starting time. Then how that is calculated.
Ranjith said:
5 years ago
Solution:
2xy/x+y >this is a formula.
2(10)(15)/10 + 15.
300/25 = 12kmph.
2xy/x+y >this is a formula.
2(10)(15)/10 + 15.
300/25 = 12kmph.
(3)
Shivasai said:
7 years ago
Then, x/10 - x/15 = 2 why we have taken this?
What is the logic behind it
What is the logic behind it
Prawesh Pradhan said:
9 years ago
After finding the distance.
60/10-60/x = 1,
6x-60 = x,
5x = 60,
x = 12.
60/10-60/x = 1,
6x-60 = x,
5x = 60,
x = 12.
Nancy said:
1 decade ago
Yes, but why we are considering only 10 km/hr speed?
Why not 15 km/hr?
Why not 15 km/hr?
Prawesh Pradhan said:
9 years ago
After finding out the distance.
60/10 - 60/x = 1,
5/x = 1,
x = 5.
60/10 - 60/x = 1,
5/x = 1,
x = 5.
Pardhu said:
1 decade ago
Thank you aamir. Is this applicable for all these type methods. ?
Ishwarya said:
7 years ago
What is the logical and easiest method for solving this problem?
ELANAGAI said:
8 years ago
How did 60/10 came in the last? Can anyone explain after that?
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