Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 14)
14.
A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot @ 4 km/hr and partly on bicycle @ 9 km/hr. The distance travelled on foot is:
Answer: Option
Explanation:
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x) km.
| So, | x | + | (61 -x) | = 9 |
| 4 | 9 |
9x + 4(61 -x) = 9 x 36
5x = 80
x = 16 km.
Discussion:
37 comments Page 3 of 4.
Mohanapriyasavithri said:
8 years ago
This can be solved easily by the rule of alligation.
Take average speed as 61÷9 (speed formula is ditance÷time).
Take the dearer value cheaper value & apply alligation rule.
Take average speed as 61÷9 (speed formula is ditance÷time).
Take the dearer value cheaper value & apply alligation rule.
JPriya said:
8 years ago
Partly means is it not (x/2 )/4+(x/2)/9=9 if d is taken as the total distance?
Please tell me.
Please tell me.
Maruti said:
8 years ago
X/4 is km ph.
(61-x)/9 is also kmph.
When these are added it should give kmph.
Why only 9 is thereafter =, why not 61/9?
Please, anyone clear my doubt.
(61-x)/9 is also kmph.
When these are added it should give kmph.
Why only 9 is thereafter =, why not 61/9?
Please, anyone clear my doubt.
(3)
Kawla said:
8 years ago
How can 5x=80? just explain it.
Amit said:
6 years ago
By Using alligation method.
4:5=9.
So, 4 * 4 = 16 by walking,
5*9 = 45 by cycle.
4:5=9.
So, 4 * 4 = 16 by walking,
5*9 = 45 by cycle.
(2)
Bindu D K said:
6 years ago
First total distance is 61km and time is 9 hour.
S=d/t, s= 61/9=6.7~6.8.
Then apply this formula for different speeds;
2xy/X+y = 6.8,
72/13 = 6.8,
72=13 * 6.8,
72-88.4 = 16.4~16.
S=d/t, s= 61/9=6.7~6.8.
Then apply this formula for different speeds;
2xy/X+y = 6.8,
72/13 = 6.8,
72=13 * 6.8,
72-88.4 = 16.4~16.
(4)
Neeraj said:
6 years ago
S = D/T.
4 = 61-x/9.
x = 16.
4 = 61-x/9.
x = 16.
(6)
Sayoo_26 said:
5 years ago
Logically, if he travels x km by feet then reaming distance should be in multiples of 9 since he had travelled remaining distance with 9kmph.
Let we try from options:
A. 14 remaining distance=61-14=47 which is not multiple of 9 since get cancelled.
B. 15 remaining distance= 61-15=46 also not multiple of 9 so cancelled.
C. 16 remaining distance=61-16=45 it's multiple of 9 so we get the answer.
Let we try from options:
A. 14 remaining distance=61-14=47 which is not multiple of 9 since get cancelled.
B. 15 remaining distance= 61-15=46 also not multiple of 9 so cancelled.
C. 16 remaining distance=61-16=45 it's multiple of 9 so we get the answer.
(5)
Puli said:
4 years ago
9 hours mean 9 times. So the procedure is;
4km, 9km,
4km, 9km,
4km, 9km,
4km, 9km.
So on foot, he travelled 16 km.
4km, 9km,
4km, 9km,
4km, 9km,
4km, 9km.
So on foot, he travelled 16 km.
(8)
Shekh Areful said:
4 years ago
From options it will be simple to solve;
61-14 = 47,
61-15 = 46,
61-16 (Dist travelled by foot) = 45, Only this is divisible by 9.
So the answer is 16.
Note: This is applicable here only because the hours are given in terms of Integers, not in fraction.
And the answer will only be the multiple of 4.
61-14 = 47,
61-15 = 46,
61-16 (Dist travelled by foot) = 45, Only this is divisible by 9.
So the answer is 16.
Note: This is applicable here only because the hours are given in terms of Integers, not in fraction.
And the answer will only be the multiple of 4.
(6)
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