Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 14)
14.
A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot @ 4 km/hr and partly on bicycle @ 9 km/hr. The distance travelled on foot is:
Answer: Option
Explanation:
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x) km.
| So, | x | + | (61 -x) | = 9 |
| 4 | 9 |
9x + 4(61 -x) = 9 x 36
5x = 80
x = 16 km.
Discussion:
37 comments Page 1 of 4.
Psan said:
4 years ago
It's very easy.
Farmer travels - 4km/hr.
Speed = 4km/hr and Time = 4 hours.
HOW?
- Well in 1 hour he travels 1 Km, then in 4 hours he will travel 4km.
So, Distance = Speed * Time.
= 4km/hr * 4hr.
= 16km (Hr gets cancel).
Farmer travels - 4km/hr.
Speed = 4km/hr and Time = 4 hours.
HOW?
- Well in 1 hour he travels 1 Km, then in 4 hours he will travel 4km.
So, Distance = Speed * Time.
= 4km/hr * 4hr.
= 16km (Hr gets cancel).
(52)
Mohamed Haakkil said:
2 years ago
61km travel in 9hours.
4kmph by foot --> taken time is "x"
9kmph by bicycle --> taken time is "y"
So,
x + y = 9 ---> (1)
Distances = speed × time.
Distance by foot--> 4 × x = 4x.
Distance by bicycle--> 9 × y = 9y.
So,
4x + 9y = 61 ----> (2)
If we solve (1) & (2) equations, we can got.
y = 5
x = 4.
So;
Distance by foot = 4x,
=4 × 4.
=16km.
4kmph by foot --> taken time is "x"
9kmph by bicycle --> taken time is "y"
So,
x + y = 9 ---> (1)
Distances = speed × time.
Distance by foot--> 4 × x = 4x.
Distance by bicycle--> 9 × y = 9y.
So,
4x + 9y = 61 ----> (2)
If we solve (1) & (2) equations, we can got.
y = 5
x = 4.
So;
Distance by foot = 4x,
=4 × 4.
=16km.
(33)
Madhav said:
4 years ago
Let the dist traveled on foot and bicycle be x&y.
Here total dis ie x + y = 61 ---> (1)
Also total time = 9,
So x/4 + y/9 =9,
9x+4y =324 ---> (2).
So, Eq 1 and 2 we get x =16, y = 45.
Here total dis ie x + y = 61 ---> (1)
Also total time = 9,
So x/4 + y/9 =9,
9x+4y =324 ---> (2).
So, Eq 1 and 2 we get x =16, y = 45.
(12)
Puli said:
4 years ago
9 hours mean 9 times. So the procedure is;
4km, 9km,
4km, 9km,
4km, 9km,
4km, 9km.
So on foot, he travelled 16 km.
4km, 9km,
4km, 9km,
4km, 9km,
4km, 9km.
So on foot, he travelled 16 km.
(8)
Neeraj said:
6 years ago
S = D/T.
4 = 61-x/9.
x = 16.
4 = 61-x/9.
x = 16.
(6)
Shekh Areful said:
4 years ago
From options it will be simple to solve;
61-14 = 47,
61-15 = 46,
61-16 (Dist travelled by foot) = 45, Only this is divisible by 9.
So the answer is 16.
Note: This is applicable here only because the hours are given in terms of Integers, not in fraction.
And the answer will only be the multiple of 4.
61-14 = 47,
61-15 = 46,
61-16 (Dist travelled by foot) = 45, Only this is divisible by 9.
So the answer is 16.
Note: This is applicable here only because the hours are given in terms of Integers, not in fraction.
And the answer will only be the multiple of 4.
(6)
Sayoo_26 said:
5 years ago
Logically, if he travels x km by feet then reaming distance should be in multiples of 9 since he had travelled remaining distance with 9kmph.
Let we try from options:
A. 14 remaining distance=61-14=47 which is not multiple of 9 since get cancelled.
B. 15 remaining distance= 61-15=46 also not multiple of 9 so cancelled.
C. 16 remaining distance=61-16=45 it's multiple of 9 so we get the answer.
Let we try from options:
A. 14 remaining distance=61-14=47 which is not multiple of 9 since get cancelled.
B. 15 remaining distance= 61-15=46 also not multiple of 9 so cancelled.
C. 16 remaining distance=61-16=45 it's multiple of 9 so we get the answer.
(5)
Bindu D K said:
6 years ago
First total distance is 61km and time is 9 hour.
S=d/t, s= 61/9=6.7~6.8.
Then apply this formula for different speeds;
2xy/X+y = 6.8,
72/13 = 6.8,
72=13 * 6.8,
72-88.4 = 16.4~16.
S=d/t, s= 61/9=6.7~6.8.
Then apply this formula for different speeds;
2xy/X+y = 6.8,
72/13 = 6.8,
72=13 * 6.8,
72-88.4 = 16.4~16.
(4)
Pushpraj said:
12 months ago
Equation 1 : DF= 4 * t1.
Equation 2 : DB= 9 * (9-t1). As distance= speed * time.
Here let t1 be time taken by foot.
Here time taken by bicycle is (total time taken - time taken by foot).
Now equate the equation;
Now DF+DB= 4t1 + 9 * (9-t1).
Now we know DF+DB is 61.
61= 4t1+81-9t1.
61=-5t1+81.
-20=-5t1.
t1=4.
So, the Time taken by foot is 4hrs.
Now distance by foot = speed * time.
D = 4 * 4 = 16 km.
Equation 2 : DB= 9 * (9-t1). As distance= speed * time.
Here let t1 be time taken by foot.
Here time taken by bicycle is (total time taken - time taken by foot).
Now equate the equation;
Now DF+DB= 4t1 + 9 * (9-t1).
Now we know DF+DB is 61.
61= 4t1+81-9t1.
61=-5t1+81.
-20=-5t1.
t1=4.
So, the Time taken by foot is 4hrs.
Now distance by foot = speed * time.
D = 4 * 4 = 16 km.
(3)
Maruti said:
8 years ago
X/4 is km ph.
(61-x)/9 is also kmph.
When these are added it should give kmph.
Why only 9 is thereafter =, why not 61/9?
Please, anyone clear my doubt.
(61-x)/9 is also kmph.
When these are added it should give kmph.
Why only 9 is thereafter =, why not 61/9?
Please, anyone clear my doubt.
(3)
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