Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 14)
14.
A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot @ 4 km/hr and partly on bicycle @ 9 km/hr. The distance travelled on foot is:
Answer: Option
Explanation:
Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x) km.
| So, | x | + | (61 -x) | = 9 |
| 4 | 9 |
9x + 4(61 -x) = 9 x 36
5x = 80
x = 16 km.
Discussion:
37 comments Page 2 of 4.
Sidzwozz said:
9 years ago
You answered very well, simple, efficient and quick. @Dihvagar.
@Suchitra.
Yes you are right but There is no option saying 20. You have to first check your options because that's where we will find out our mistakes in calculation.
@Suchitra.
Yes you are right but There is no option saying 20. You have to first check your options because that's where we will find out our mistakes in calculation.
Madhav said:
4 years ago
Let the dist traveled on foot and bicycle be x&y.
Here total dis ie x + y = 61 ---> (1)
Also total time = 9,
So x/4 + y/9 =9,
9x+4y =324 ---> (2).
So, Eq 1 and 2 we get x =16, y = 45.
Here total dis ie x + y = 61 ---> (1)
Also total time = 9,
So x/4 + y/9 =9,
9x+4y =324 ---> (2).
So, Eq 1 and 2 we get x =16, y = 45.
(12)
Xyz said:
1 decade ago
Given that total distance travelled=61km and total time=9hrs.
Let x be the distance by foot.
And 61-x be the distance by bicycle.
s=d/t t=d/s.
9=x/4+ (61-x) /9.
By solving we gt 16 km.
Let x be the distance by foot.
And 61-x be the distance by bicycle.
s=d/t t=d/s.
9=x/4+ (61-x) /9.
By solving we gt 16 km.
Mohanapriyasavithri said:
8 years ago
This can be solved easily by the rule of alligation.
Take average speed as 61÷9 (speed formula is ditance÷time).
Take the dearer value cheaper value & apply alligation rule.
Take average speed as 61÷9 (speed formula is ditance÷time).
Take the dearer value cheaper value & apply alligation rule.
Bindu D K said:
6 years ago
First total distance is 61km and time is 9 hour.
S=d/t, s= 61/9=6.7~6.8.
Then apply this formula for different speeds;
2xy/X+y = 6.8,
72/13 = 6.8,
72=13 * 6.8,
72-88.4 = 16.4~16.
S=d/t, s= 61/9=6.7~6.8.
Then apply this formula for different speeds;
2xy/X+y = 6.8,
72/13 = 6.8,
72=13 * 6.8,
72-88.4 = 16.4~16.
(4)
Grandmaster said:
1 decade ago
Simplest way is by grandmaster is:
Lets take % first: 4/9*100.
44.444444%.
Total time travelled: 540 mins.
44.444444% of 540 = 240 mins = 4 hrs.
Distance = 4*4 = 16 hrs.
Lets take % first: 4/9*100.
44.444444%.
Total time travelled: 540 mins.
44.444444% of 540 = 240 mins = 4 hrs.
Distance = 4*4 = 16 hrs.
Laxmibhavani.B said:
1 decade ago
@Tiru it's simple.
9 = x/4 + (61-x)/9...(1)
now take L.C.M for 4 and 9 i.e 36
9=(9x+4(61-x))/36
cross multiply
9*36=9x+244-4x
324=5x+244
5x=324-244
5x=80
x=80/5
x=16km
9 = x/4 + (61-x)/9...(1)
now take L.C.M for 4 and 9 i.e 36
9=(9x+4(61-x))/36
cross multiply
9*36=9x+244-4x
324=5x+244
5x=324-244
5x=80
x=80/5
x=16km
Maruti said:
8 years ago
X/4 is km ph.
(61-x)/9 is also kmph.
When these are added it should give kmph.
Why only 9 is thereafter =, why not 61/9?
Please, anyone clear my doubt.
(61-x)/9 is also kmph.
When these are added it should give kmph.
Why only 9 is thereafter =, why not 61/9?
Please, anyone clear my doubt.
(3)
Jarman said:
1 decade ago
Total distance =61 km.
Let distance travelled by foot = x.
Let distance travelled by bicycle = y.
So, x+y = 61.
Also from above equation.
y = 61-x.
Let distance travelled by foot = x.
Let distance travelled by bicycle = y.
So, x+y = 61.
Also from above equation.
y = 61-x.
SID said:
1 decade ago
Well I have gotta doubt.
The equation which I made is (61-x)/4 + x/9 = 9.
And the answers which I am getting is 41 km/hr and 20 km/hr.
PLEASE HELP.
The equation which I made is (61-x)/4 + x/9 = 9.
And the answers which I am getting is 41 km/hr and 20 km/hr.
PLEASE HELP.
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