Aptitude - Surds and Indices - Discussion
Discussion Forum : Surds and Indices - General Questions (Q.No. 8)
8.
1 | + | 1 | + | 1 | = ? |
1 + x(b - a) + x(c - a) | 1 + x(a - b) + x(c - b) | 1 + x(b - c) + x(a - c) |
Answer: Option
Explanation:
Given Exp. = |
|
= | xa | + | xb | + | xc |
(xa + xb + xc) | (xa + xb + xc) | (xa + xb + xc) |
= | (xa + xb + xc) |
(xa + xb + xc) |
= 1.
Discussion:
24 comments Page 3 of 3.
Nisha said:
1 decade ago
Have any short cut method?
Rutuja said:
3 years ago
It's great. Thanks all.
Ragav said:
7 years ago
Here, assign x=1.
Shekhar kushwaha said:
10 years ago
What if x = 0?
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