Aptitude - Surds and Indices - Discussion
Discussion Forum : Surds and Indices - General Questions (Q.No. 8)
8.
1 | + | 1 | + | 1 | = ? |
1 + x(b - a) + x(c - a) | 1 + x(a - b) + x(c - b) | 1 + x(b - c) + x(a - c) |
Answer: Option
Explanation:
Given Exp. = |
|
= | xa | + | xb | + | xc |
(xa + xb + xc) | (xa + xb + xc) | (xa + xb + xc) |
= | (xa + xb + xc) |
(xa + xb + xc) |
= 1.
Discussion:
24 comments Page 1 of 3.
Raju said:
1 decade ago
I didn't understand the second line.
Kunaman said:
1 decade ago
@raju
We took the lcm of the denominator of the expression 1+x^b/x^a...
We took the lcm of the denominator of the expression 1+x^b/x^a...
Nisha said:
1 decade ago
Have any short cut method?
Vasundhara said:
1 decade ago
It is the shortcut and easiest way to solve this problem.
Arshad said:
1 decade ago
I did not understood second step from last.
Can you please explain in detail(only last two steps)
How do you consider x^a+x^b+x^c in numerator ?(x^a+x^b+x^c/x^a+x^b+x^c)
Can you please explain in detail(only last two steps)
How do you consider x^a+x^b+x^c in numerator ?(x^a+x^b+x^c/x^a+x^b+x^c)
Sagar said:
1 decade ago
The second step is derived from first step by multiplying numerator & denominator of each of the 3 components with x^a, x^b & x^c respectively.
Anagha said:
1 decade ago
How do you solve the second step? Really confusing, please do it the long way so we can understand.
Abhijeet singh said:
1 decade ago
In the second line just take the LCM. and make the adjustment accordingly.
Its very simple try it on paper itself.
You guys will get the answer.
Thank you.
Its very simple try it on paper itself.
You guys will get the answer.
Thank you.
Shekhar kushwaha said:
10 years ago
What if x = 0?
KazirangaUniv said:
10 years ago
From the second step:
x^a(x^a+x^b+x^c)^2+x^b(x^a+x^b+x^c)^2+x^c(x^a+x^b+x^c)^2/(x^a+x^b+x^c)^3
Then take (x^a+X^b+x^c)^2 common from numerator and denominator and cut them both from top and bottom. Then we get step 3.
x^a(x^a+x^b+x^c)^2+x^b(x^a+x^b+x^c)^2+x^c(x^a+x^b+x^c)^2/(x^a+x^b+x^c)^3
Then take (x^a+X^b+x^c)^2 common from numerator and denominator and cut them both from top and bottom. Then we get step 3.
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