Aptitude - Surds and Indices - Discussion

Discussion Forum : Surds and Indices - General Questions (Q.No. 8)

Surds and Indices

1	+	1	+	1	= ?
1 + x^{(b - a)} + x^{(c - a)}		1 + x^{(a - b)} + x^{(c - b)}		1 + x^{(b - c)} + x^{(a - c)}

x^{a - b - c}

None of these

Answer: Option

Explanation:

Given Exp. =

	1 +	x^b	+	x^c
		x^a		x^a

	1 +	x^a	+	x^c
		x^b		x^b

	1 +	x^b	+	x^a
		x^c		x^c

=	x^a	+	x^b	+	x^c
	(x^a + x^b + x^c)		(x^a + x^b + x^c)		(x^a + x^b + x^c)

=	(x^a + x^b + x^c)
	(x^a + x^b + x^c)

= 1.

Discussion:

24 comments Page 2 of 3.

Garima said: 8 years ago

Short cut method.

Let a=b=c=1.
We get 1/3 +1/3 +1/3 =3/ 3 =1.

(1)

Vasundhara said: 1 decade ago

It is the shortcut and easiest way to solve this problem.

Franklin Emeka said: 9 years ago

I am not understanding this. Any of them can explain me?

Aarambh said: 8 years ago

I cannot understand the second step. Please explain me.

Akshita Tank said: 10 years ago

Can anybody explain the question in easier way?

Ayush said: 8 years ago

@Garima

How? Please explain in detail.

Shantanu Gupta said: 5 years ago

Here,

a, b, and c in cyclic order = 1.

John said: 3 years ago

Thanks all for explaining the answer.

Raju said: 1 decade ago

I didn't understand the second line.

Favour said: 9 years ago

I do not understand any of them.

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