Aptitude - Surds and Indices - Discussion

Discussion Forum : Surds and Indices - General Questions (Q.No. 8)

Surds and Indices

1	+	1	+	1	= ?
1 + x^{(b - a)} + x^{(c - a)}		1 + x^{(a - b)} + x^{(c - b)}		1 + x^{(b - c)} + x^{(a - c)}

x^{a - b - c}

None of these

Answer: Option

Explanation:

Given Exp. =

	1 +	x^b	+	x^c
		x^a		x^a

	1 +	x^a	+	x^c
		x^b		x^b

	1 +	x^b	+	x^a
		x^c		x^c

=	x^a	+	x^b	+	x^c
	(x^a + x^b + x^c)		(x^a + x^b + x^c)		(x^a + x^b + x^c)

=	(x^a + x^b + x^c)
	(x^a + x^b + x^c)

= 1.

Discussion:

24 comments Page 3 of 3.

Arshad said: 1 decade ago

I did not understood second step from last.

Can you please explain in detail(only last two steps)

How do you consider x^a+x^b+x^c in numerator ?(x^a+x^b+x^c/x^a+x^b+x^c)

Vasundhara said: 1 decade ago

It is the shortcut and easiest way to solve this problem.

Nisha said: 1 decade ago

Have any short cut method?

Kunaman said: 1 decade ago

@raju

We took the lcm of the denominator of the expression 1+x^b/x^a...

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