Aptitude - Surds and Indices - Discussion
Discussion Forum : Surds and Indices - General Questions (Q.No. 8)
8.
| 1 | + | 1 | + | 1 | = ? |
| 1 + x(b - a) + x(c - a) | 1 + x(a - b) + x(c - b) | 1 + x(b - c) + x(a - c) |
Answer: Option
Explanation:
| Given Exp. = |
|
| = | xa | + | xb | + | xc |
| (xa + xb + xc) | (xa + xb + xc) | (xa + xb + xc) |
| = | (xa + xb + xc) |
| (xa + xb + xc) |
= 1.
Discussion:
24 comments Page 2 of 3.
Ekta said:
8 years ago
In the second line,the denominator is solved as:-
(1+x^b/x^a+x^c/x^a) (solving 1st denominator of the first fraction)
Which comes as( x^a+x^b+x^c)/x^a.
Now, the first fraction is : 1/((x^a+x^b+x^c)/x^a) which can be also written as x^a/(x^a+x^b+x^c).
Similarly other two fractions are also solved and finally x^a/(x^a+x^b+x^c) + x^b/(x^a+x^b+x^c) + x^c/(x^a+x^b+x^c) = 1.
(1+x^b/x^a+x^c/x^a) (solving 1st denominator of the first fraction)
Which comes as( x^a+x^b+x^c)/x^a.
Now, the first fraction is : 1/((x^a+x^b+x^c)/x^a) which can be also written as x^a/(x^a+x^b+x^c).
Similarly other two fractions are also solved and finally x^a/(x^a+x^b+x^c) + x^b/(x^a+x^b+x^c) + x^c/(x^a+x^b+x^c) = 1.
Franklin Emeka said:
9 years ago
I am not understanding this. Any of them can explain me?
Raju said:
1 decade ago
I didn't understand the second line.
Achitsa said:
9 years ago
First solve the denominator using LCM the answer you get. Find its reciprocal.
Akshita Tank said:
10 years ago
Can anybody explain the question in easier way?
Shekhar kushwaha said:
10 years ago
What if x = 0?
KazirangaUniv said:
10 years ago
From the second step:
x^a(x^a+x^b+x^c)^2+x^b(x^a+x^b+x^c)^2+x^c(x^a+x^b+x^c)^2/(x^a+x^b+x^c)^3
Then take (x^a+X^b+x^c)^2 common from numerator and denominator and cut them both from top and bottom. Then we get step 3.
x^a(x^a+x^b+x^c)^2+x^b(x^a+x^b+x^c)^2+x^c(x^a+x^b+x^c)^2/(x^a+x^b+x^c)^3
Then take (x^a+X^b+x^c)^2 common from numerator and denominator and cut them both from top and bottom. Then we get step 3.
Abhijeet singh said:
1 decade ago
In the second line just take the LCM. and make the adjustment accordingly.
Its very simple try it on paper itself.
You guys will get the answer.
Thank you.
Its very simple try it on paper itself.
You guys will get the answer.
Thank you.
Anagha said:
1 decade ago
How do you solve the second step? Really confusing, please do it the long way so we can understand.
Sagar said:
1 decade ago
The second step is derived from first step by multiplying numerator & denominator of each of the 3 components with x^a, x^b & x^c respectively.
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