Aptitude - Surds and Indices - Discussion

Discussion Forum : Surds and Indices - General Questions (Q.No. 12)

Surds and Indices

12.

1	+	1	= ?
1 + a^{(n - m)}		1 + a^{(m - n)}

a^{m + n}

Answer: Option

Explanation:

	1 +	aⁿ
		a^m

	1 +	a^m
		aⁿ

1 + a^{(n - m)}

1 + a^{(m - n)}

=	a^m	+	aⁿ
	(a^m + aⁿ)		(a^m + aⁿ)

=	(a^m + aⁿ)
	(a^m + aⁿ)

= 1.

Discussion:

9 comments Page 1 of 1.

Karthik said: 9 years ago

Please solve this sum in details with DIRECTION TO SIMPLIFY EACH VALUES.

(1)

Kedar said: 4 years ago

The answer should be a^m+n.

(1)

Sunny kumar said: 1 decade ago

Could anybody please help me with this as where both 1's in numerator gone?

Thanks.

Rianshi Sharma said: 8 years ago

Step 1. Take negative power as denominator of positive power.
Step 2. LCM the whole thing.
Step 3. You will get the Result.

Nischal said: 8 years ago

Please explain the last step.

Mohit said: 8 years ago

The answer should been 1/2.

Ragav said: 7 years ago

Here, assign a=1.

Amisha said: 3 years ago

Please explain it briefly.

Rahul said: 3 years ago

Assume m=n,
So 1/2+1/2 = 1.

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