Aptitude - Surds and Indices - Discussion
Discussion Forum : Surds and Indices - General Questions (Q.No. 13)
13.
If m and n are whole numbers such that mn = 121, the value of (m - 1)n + 1 is:
Answer: Option
Explanation:
We know that 112 = 121.
Putting m = 11 and n = 2, we get:
(m - 1)n + 1 = (11 - 1)(2 + 1) = 103 = 1000.
Discussion:
13 comments Page 1 of 2.
Surbhi said:
6 years ago
Simple if the statement said m^ =121.
m^=11 to the power 2.
Therefore m=11.
^ = 2.
(^) this is assigned by n.
m^=11 to the power 2.
Therefore m=11.
^ = 2.
(^) this is assigned by n.
(2)
Asad said:
3 years ago
@All.
It's surds and indices math.
The square root should be surds. That's why we cant take -11, 121.
It's surds and indices math.
The square root should be surds. That's why we cant take -11, 121.
Krishna said:
1 decade ago
For 121 it is ok, if it is not 121 then?
if 16, we can assume 2^4 or 4^2.
is there other method ?
if 16, we can assume 2^4 or 4^2.
is there other method ?
Ali said:
3 years ago
But it is given that it is a whole number so it can't be negative (-11).
Am I right?
Am I right?
Siri said:
10 years ago
How can we assumed exact n value as 2 here as a natural number are whole number.
Name said:
9 years ago
Why we have taken m = 11 and n = 2 here? We can also take m= 121 and n = 1.
(1)
Kanishka Roy said:
3 years ago
This is wrong method because the value of m can easily be -11.
Naren said:
9 years ago
120^2 is exactly right until we have related options.
(1)
Ankit Agarwal said:
1 decade ago
121^1 so m=121 n=1 in this case answer is 120^2.
Sowmi said:
9 years ago
It is doubtful. Please give the answer clearly.
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