Aptitude - Surds and Indices - Discussion
Discussion Forum : Surds and Indices - General Questions (Q.No. 15)
15.
| If x = 3 + 22, then the value of |  |
x | - | 1 |  |
is: |
| x |
Answer: Option
Explanation:
|
x | - | 1 | |
2 | = x + | 1 | - 2 |
| x | x |
| = (3 + 22) + | 1 | - 2 |
| (3 + 22) |
| = (3 + 22) + | 1 | x | (3 - 22) | - 2 |
| (3 + 22) | (3 - 22) |
= (3 + 22) + (3 - 22) - 2
= 4.
 |
|
x | - | 1 | |
= 2. |
| x |
Discussion:
48 comments Page 4 of 5.
Felix said:
8 years ago
How did you obtain 1/x +x -2?
(3)
Akashdeep Singh said:
8 years ago
In the last stage where we find the value of [(underoot)x - 1/(underoot)x]^2 = 4.
So if you remove the square then it will become (underoot)4 i.e. 2.
(underoot)x - 1/(underoot)x = (underoot)4.
(underoot)x - 1/(underoot)x = 2.
So if you remove the square then it will become (underoot)4 i.e. 2.
(underoot)x - 1/(underoot)x = (underoot)4.
(underoot)x - 1/(underoot)x = 2.
Bishal Dey said:
8 years ago
= 3+2√2 + 1/3+2√2 -2,
= 3+2√2 + 3 - 2√2 -2,
=6-2.
=4.
=√4=2.
= 3+2√2 + 3 - 2√2 -2,
=6-2.
=4.
=√4=2.
Harigovind C B said:
8 years ago
if a÷b=4÷5 and b÷c=15÷16 , then (c^2-a^2)÷c^2+a^2 is equal to?
Can anyone solve this?
Can anyone solve this?
Mahima said:
8 years ago
4th step how to solve the denominator (3+2√2)(3-2√2)? Please explain.
BFC said:
7 years ago
How to solve 4th step the denominator (3+2√2) (3-2√2)? Please explain.
Milind said:
7 years ago
(√x-1/√) -2 = (x + 1/x) - 2.
Can you tell me where this -2 comes from?
Can you tell me where this -2 comes from?
Mohan said:
6 years ago
@Joe.
In the first step, it is in the form of (a-b) ^2 formula.
In the first step, it is in the form of (a-b) ^2 formula.
Abisheak said:
6 years ago
Where is the power 2 comes from in the starting stage? We can See that there is no power mentioned in the question.
Rakshith said:
6 years ago
@Abisheak.
We have taken that power to get the equation and rooted in the final to get the answer.
We have taken that power to get the equation and rooted in the final to get the answer.
(1)
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