Aptitude - Simplification - Discussion

Discussion :: Simplification - General Questions (Q.No.5)

5. 

The price of 2 sarees and 4 shirts is Rs. 1600. With the same money one can buy 1 saree and 6 shirts. If one wants to buy 12 shirts, how much shall he have to pay ?

[A]. Rs. 1200
[B]. Rs. 2400
[C]. Rs. 4800
[D]. Cannot be determined
[E]. None of these

Answer: Option B

Explanation:

Let the price of a saree and a shirt be Rs. x and Rs. y respectively.

Then, 2x + 4y = 1600 .... (i)

    and x + 6y = 1600 .... (ii)


Divide equation (i) by 2, we get the below equation. 

=> x +  2y =  800. --- (iii)

Now subtract (iii) from (ii)

 x +  6y = 1600  (-)
 x +  2y =  800  
----------------
      4y =  800
----------------

Therefore, y = 200.

Now apply value of y in (iii)

=>  x + 2 x 200 = 800

=>  x + 400 = 800

Therefore x = 400

Solving (i) and (ii) we get x = 400, y = 200.

Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.


Sun said: (Oct 7, 2010)  
2Sarees+4shirts=1600----equation(1)
1saree+6shirts=1600------equation(2) Since it has been given that same amount.

Now solve these equations
2s+4shirts=1600
2s+12shirts=3200 (multiply by 2 to solve)

Now we get 8 shirts = 1600 i.e; 1 shirt = 200 and 2 s+4*200 = 1600 => 2s=800 i.e; 1 saree cost 400.

and now we want 12shirts cost. So 200*12 = 2400.

Hope you understood.

Nishanthi said: (Jan 12, 2011)  
Let,
Number of saree=x
Number of shirt=y

Given, 2x+4y=1600 & x+6y=1600

So solving the above equations:

1-> 2x+4y=1600
2-> 2x+12y=3200 [Mul equ 2 by 2]
_____________
-8y=-1600
_____________

So, y=200

Then we have to find 12 shirts Rs (i.e,)=12y=12*200=2400.

Naddy said: (Jan 15, 2011)  
2x+4y=1600...1
2x+4y=x+6y
x=2y....2
sub in ....1
2(2y)+4y =1600
8y=1600
y=200

so for 12 shirts, 12(200)=2400

Dilip said: (Jan 28, 2011)  
a=sarees
b=shirts

2a+4b=1600...(1)
a+6b=1600...(2)

(2)*2 = 2a+12b=3600

(2)-(1)
2a+12b=3600
2a+4b=1600
8b=1600
b=200

12(200)=2400

Sukant said: (Mar 18, 2011)  
Easy one...............
2X+4Y=X+6Y
=>X=2Y
2 saree=4 shirts
=4+4 = 8
8-1600
1-200
12-2400

Ravi Kiran said: (Oct 4, 2011)  
Thanks nishanthi!

Manasa said: (Oct 11, 2011)  
2saree+4shirt=1600 ........(1)
1saree+6shirt=1600 ........(2)
then 1saree-2shirt=0
=>1sharee=2shirt
then from equation (1),
4shirt+4shirt=1600
=>8shirt=1600
=>1shirt=200
=>12shirt=2400

Lakshmi Narayana.N said: (Jan 7, 2012)  
We equal the both equations then we get
2x+4y=x+6y
2x-x=6y-4y
x=2y

Then substitute this in equation we get
2y+6y=1600
8y=1600
y=200

x=2y
x=2*200=400

Cost of 12 shirts = 12*200 = 2400.

Raj said: (Oct 27, 2012)  
May be this is also useful
Think!

2 sarees+ 4 shirts=1600
1 sarees+ 6 shirts=1600
0 saries+ 8 shirts=1600

Now 1s=200rs
12s=2400.

Baiju V T said: (Nov 22, 2012)  
Simple.

2 sarees + 4 shirts =1600.

400*2=800 and 200*4=800,

800+800 =1600.

1 saree + 6 shirts=1600.

400*1=400 and 200*6=1200.

400+1200=1600 (one saree prize is 400 and one shirt prize is 200).

So the prize of the 12 shirts are. 200*12=2400.

Dipika said: (May 23, 2013)  
1 saree = 2 shirts.
2 sarees + 4 shirts = 1600.
6 sarees = 1600.
1 saree = 400.
1 shirt = 200.
12 shirt = 12 * 200 = 2400.

Vinitha said: (Feb 3, 2014)  
Hai @Dipika, can you please explain mathematically?

Jooly said: (Jun 11, 2014)  
let X denotes saree and y denotes Shirt.
From the question,

2x+4y = 1600 ..........(1).
x+6y =1600 ..............(2).

From eqn (1) and (2).
2x+4y = x+6y
2x-x = 6y-4y
or x = 2y..................(3).

Put the value of x in eqn (2).
2y+6y = 1600.
8y =1600.
y =200.

Put the value of y in eqn (3) we get the value of saree that is :
x = 2y = 400.
1 saree = 400.
1 shirt = 200.
12 shirt = 12 * 200 = 2400.

Vishal said: (Oct 5, 2014)  
Given 2 sarees & 4 shirts= 1600 ......(1).
With same many he can buy 1 saree & 6 shirts.

Therefore 1 saree cost = 2 shirts cost.
Hence 2 saree = 4 shirts.

In (1) 8 shirts = 1600.

1 shirt = 200.
12 shirts = 2400.

Aparna said: (Jul 16, 2015)  
2 sarees + 4 shirts = 1600 equation1*6 = 12 sarees + 24 shirts = 9600.

1 saree + 6 shirts = 1600 equation2*4 = 4 sarees + 24 shirts = 6400.

8 sarees = 3200.
1 saree = 400.

Is this process is correct or wrong if wrong can you tell me why it is wrong so that I will come to know please help me to get the answer.

Murali said: (Aug 27, 2015)  
2 sarees+4 shirts=1600.

Then the ratio is 1:2.
Simply 1600/2=800.

Then 2 sarees cost 800.
4 shirts cost 800.

800/4=200 one shirt value is 200 only.

Lakhan Yadav said: (Oct 21, 2016)  
Subtract from 1 and 2 gets 1 sarees = 2 shirts.
Put into Eqn 1 and gets values of shirt which is 200.
After that 12 * 200 = 2400.

Sandeep Choudhary said: (May 12, 2018)  
2s+4y=1600,
1s+6y=1600,
S=2y.
2y+6y=1600,
Y=200,
12y=12*200=2400.

Venkat said: (Feb 12, 2019)  
Thanks @Naddy.

Ameer said: (Mar 19, 2019)  
Thank you @Sandeep Choudhary.

Sonu Ansari said: (Jun 15, 2019)  
2 sari +4 shirt = 1600.
1 sari + 6 shirt = 1600.

It means when one sari decreased than 2 more shirts can be bought
So;

1 sari + 6 shirts can be equal to 8 shirts.
8 shirt=1600,
1 shirt =200,

Now cost of 12 shirts =12*200 = 2400.

Diksha Aggarwal said: (May 28, 2020)  
Let the price of saree and shirt be x and y.

2x + 4y =1600,
x+6y= 1600,
2(x+6y=1600) => 2x + 12y=3200.
8y=1600,
y=1600/8,
y=200,
12*200,
Price = 2400.

Parveen Sathik said: (Nov 22, 2020)  
Thank you @Diksha.

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