# Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 5)

5.

The price of 2 sarees and 4 shirts is Rs. 1600. With the same money one can buy 1 saree and 6 shirts. If one wants to buy 12 shirts, how much shall he have to pay ?

Answer: Option

Explanation:

Let the price of a saree and a shirt be Rs. *x* and Rs. *y* respectively.

Then, 2*x* + 4*y* = 1600 .... (i)

and *x* + 6*y* = 1600 .... (ii)

Divide equation (i) by 2, we get the below equation. => x + 2y = 800. --- (iii) Now subtract (iii) from (ii) x + 6y = 1600 (-) x + 2y = 800 ---------------- 4y = 800 ---------------- Therefore, y = 200. Now apply value of y in (iii) => x + 2 x 200 = 800 => x + 400 = 800 Therefore x = 400

Solving (i) and (ii) we get *x* = 400, *y* = 200.

Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.

Discussion:

24 comments Page 1 of 3.
Singye said:
2 years ago

It can be also solved as

Let the cost of the saree and shirts be x and y respectively.

Given;

2x+4y = 1x+6y.

Solving

X = 2y.

Now substitute the above value in 2x + 4y = 1600.

2(2y) + 4y = 1600,

4y + 4y = 1600,

Therefore, y = 200,

12*200 = 2400.

Let the cost of the saree and shirts be x and y respectively.

Given;

2x+4y = 1x+6y.

Solving

X = 2y.

Now substitute the above value in 2x + 4y = 1600.

2(2y) + 4y = 1600,

4y + 4y = 1600,

Therefore, y = 200,

12*200 = 2400.

(23)

Parveen Sathik said:
4 years ago

Thank you @Diksha.

(1)

Diksha Aggarwal said:
4 years ago

Let the price of saree and shirt be x and y.

2x + 4y =1600,

x+6y= 1600,

2(x+6y=1600) => 2x + 12y=3200.

8y=1600,

y=1600/8,

y=200,

12*200,

Price = 2400.

2x + 4y =1600,

x+6y= 1600,

2(x+6y=1600) => 2x + 12y=3200.

8y=1600,

y=1600/8,

y=200,

12*200,

Price = 2400.

(4)

Sonu Ansari said:
5 years ago

2 sari +4 shirt = 1600.

1 sari + 6 shirt = 1600.

It means when one sari decreased than 2 more shirts can be bought

So;

1 sari + 6 shirts can be equal to 8 shirts.

8 shirt=1600,

1 shirt =200,

Now cost of 12 shirts =12*200 = 2400.

1 sari + 6 shirt = 1600.

It means when one sari decreased than 2 more shirts can be bought

So;

1 sari + 6 shirts can be equal to 8 shirts.

8 shirt=1600,

1 shirt =200,

Now cost of 12 shirts =12*200 = 2400.

(15)

Ameer said:
6 years ago

Thank you @Sandeep Choudhary.

Venkat said:
6 years ago

Thanks @Naddy.

(1)

Sandeep choudhary said:
6 years ago

2s+4y=1600,

1s+6y=1600,

S=2y.

2y+6y=1600,

Y=200,

12y=12*200=2400.

1s+6y=1600,

S=2y.

2y+6y=1600,

Y=200,

12y=12*200=2400.

(1)

Lakhan yadav said:
8 years ago

Subtract from 1 and 2 gets 1 sarees = 2 shirts.

Put into Eqn 1 and gets values of shirt which is 200.

After that 12 * 200 = 2400.

Put into Eqn 1 and gets values of shirt which is 200.

After that 12 * 200 = 2400.

Murali said:
9 years ago

2 sarees+4 shirts=1600.

Then the ratio is 1:2.

Simply 1600/2=800.

Then 2 sarees cost 800.

4 shirts cost 800.

800/4=200 one shirt value is 200 only.

Then the ratio is 1:2.

Simply 1600/2=800.

Then 2 sarees cost 800.

4 shirts cost 800.

800/4=200 one shirt value is 200 only.

Aparna said:
9 years ago

2 sarees + 4 shirts = 1600 equation1*6 = 12 sarees + 24 shirts = 9600.

1 saree + 6 shirts = 1600 equation2*4 = 4 sarees + 24 shirts = 6400.

8 sarees = 3200.

1 saree = 400.

Is this process is correct or wrong if wrong can you tell me why it is wrong so that I will come to know please help me to get the answer.

1 saree + 6 shirts = 1600 equation2*4 = 4 sarees + 24 shirts = 6400.

8 sarees = 3200.

1 saree = 400.

Is this process is correct or wrong if wrong can you tell me why it is wrong so that I will come to know please help me to get the answer.

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