Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 1)
1.
A man has Rs.480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
Answer: Option
Explanation:
Let number of notes of each denomination be x.
Then x + 5x + 10x = 480
16x = 480
x = 30.
Hence, total number of notes = 3x = 90.
Discussion:
77 comments Page 5 of 8.
Sagar said:
6 years ago
Thanks @Ramesh.
Kalyani said:
7 years ago
Thanks all for explaining.
Manojit said:
1 decade ago
Thank you Ramesh..
Sayalee said:
1 decade ago
Can you tel me if denomination is not equal what will be method.
Hari said:
1 decade ago
Divide the notes 30*10 = 300.
30*5 = 150.
30*1 = 30.
Add = 300+150+30 = 480.
No of notes = 90.
30*5 = 150.
30*1 = 30.
Add = 300+150+30 = 480.
No of notes = 90.
Vinitha said:
1 decade ago
I think it's may be wrong @Jayakrishna. How can you get x=90?
Can you please explain it?
Can you please explain it?
JayaKrishna said:
1 decade ago
Please tell me is this solution is correct?
((1*x+2*x+3*x)/3) = 480.
So x = 90.
((1*x+2*x+3*x)/3) = 480.
So x = 90.
Amit tomar said:
1 decade ago
When No.of rupees are different denomination so how we can take 3x for total No.of rupees.
Rohit said:
1 decade ago
If anybody have doubt on ramesh's trick (method of solving) then they can make their own example and try, you will come to know.
Raghu said:
1 decade ago
Thanks to @Ramesh your explanation is clear but all problems are same pattern this formula use it or not tell me.
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