Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 1)
1.
A man has Rs.480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
45
60
75
90
Answer: Option
Explanation:

Let number of notes of each denomination be x.

Then x + 5x + 10x = 480

16x = 480

x = 30.

Hence, total number of notes = 3x = 90.

Discussion:
77 comments Page 2 of 8.

Manojit said:   1 decade ago
Thank you Ramesh..

Sumit said:   1 decade ago
Thanks ramesh very easy form of method.

Deep goel said:   1 decade ago
x+5y+10z=480 -> 1.
x=y=z -> 2.
x+y+z=? -> 3.

From 2 we can say that
x+5x+10x=480.

16x=480 : x=30.
From 2&3 we get answer as 30+30+30=90.
(1)

Raghu said:   1 decade ago
Thanks to @Ramesh your explanation is clear but all problems are same pattern this formula use it or not tell me.

Rohit said:   1 decade ago
If anybody have doubt on ramesh's trick (method of solving) then they can make their own example and try, you will come to know.

Amit tomar said:   1 decade ago
When No.of rupees are different denomination so how we can take 3x for total No.of rupees.

JayaKrishna said:   1 decade ago
Please tell me is this solution is correct?

((1*x+2*x+3*x)/3) = 480.

So x = 90.

Vinitha said:   1 decade ago
I think it's may be wrong @Jayakrishna. How can you get x=90?

Can you please explain it?

Hari said:   1 decade ago
Divide the notes 30*10 = 300.
30*5 = 150.
30*1 = 30.

Add = 300+150+30 = 480.

No of notes = 90.

Sayalee said:   1 decade ago
Can you tel me if denomination is not equal what will be method.


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