Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 6)
                   
                                       
                                6.
A sum of Rs. 1360 has been divided among A, B and C such that A gets 
 of what B gets and B gets 
 of what C gets. B's share is:
 
                                    
 of what B gets and B gets 
 of what C gets. B's share is:
Answer: Option
                                                    Explanation:
                                                Let C's share = Rs. x
| Then, B's share = Rs. | x | , A's share = Rs. | ![]()  | 
    2 | x | x | ![]()  | 
    = Rs. | x | 
| 4 | 3 | 4 | 6 | 
![]()  | 
    x | + | x | + x = 1360 | 
| 6 | 4 | 
![]()  | 
    17x | = 1360 | 
| 12 | 
  x = | 
    1360 x 12 | = Rs. 960 | 
| 17 | 
| Hence, B's share = Rs. | ![]()  | 
    960 | ![]()  | 
    = Rs. 240. | 
| 4 | 
Discussion:
34 comments Page 3 of 4.
                
                        Renu said: 
                         
                        1 decade ago
                
                Guys am very confused for this question please provide a simple way to solve this question.
                
                        Shreemoyee said: 
                         
                        1 decade ago
                
                How can it come?
                
                        Vishal said: 
                         
                        1 decade ago
                
                Lets we do this problem in ratio method. 
Given B gets 1/4 what of what c gets & A gets 2/3 of what B gets,
Lets c gets x, then B = x/4, then a gets 2/3(x/4) = x/6.
Hence A: B: C = x/6 : x/4 : x.
              
Hence A: B: C: = 2:3:12.
There fore the share of B is 3/17(1360) = 240.
                Given B gets 1/4 what of what c gets & A gets 2/3 of what B gets,
Lets c gets x, then B = x/4, then a gets 2/3(x/4) = x/6.
Hence A: B: C = x/6 : x/4 : x.
Hence A: B: C: = 2:3:12.
There fore the share of B is 3/17(1360) = 240.
                     (1)
                
            
                        Shivam said: 
                         
                        1 decade ago
                
                let C be x.
//B gets 1/4 of what C gets means(of means multiply).
//What is C, C=x,
B=1/4 * C i.e.(1/4 * x) =>x/4.
// A gets 2/3 of what B gets means.
// What is B, B=x/4.
A=2/3*B i.e.(2/3 * x/4) => x/6.
Adding all means A + B + C.
x/6 + x/4 + x.
Taking an LCM of 6,4 i.e. 12.
This means 2x+3x+12x/12 => 17x/12.
=>17x/12=1360 => x= 1360*12/17 i.e.=> x= 960.
Put In B Share(means x/4) i.e. =>960/4=240.
Got it.
                //B gets 1/4 of what C gets means(of means multiply).
//What is C, C=x,
B=1/4 * C i.e.(1/4 * x) =>x/4.
// A gets 2/3 of what B gets means.
// What is B, B=x/4.
A=2/3*B i.e.(2/3 * x/4) => x/6.
Adding all means A + B + C.
x/6 + x/4 + x.
Taking an LCM of 6,4 i.e. 12.
This means 2x+3x+12x/12 => 17x/12.
=>17x/12=1360 => x= 1360*12/17 i.e.=> x= 960.
Put In B Share(means x/4) i.e. =>960/4=240.
Got it.
                        Bhavana said: 
                         
                        1 decade ago
                
                To say the truth I didn't understand any of the methods. Can any one explain it clearly.
                
                        Sunny said: 
                         
                        1 decade ago
                
                Every thing is ok but how can we calculate the 17?
                
                        Sure said: 
                         
                        1 decade ago
                
                How come B is equal 1/4(X) ?
                
                        Kiran said: 
                         
                        1 decade ago
                
                A:B = 2:3.
B:C = 1:4.
A:B:C = 2:3:12.
Total parts = 2+3+12+17 parts.
17 parts = 1360.
B's share is 3 parts.
Then (1360*3)/17.
= 240.
                B:C = 1:4.
A:B:C = 2:3:12.
Total parts = 2+3+12+17 parts.
17 parts = 1360.
B's share is 3 parts.
Then (1360*3)/17.
= 240.
                     (1)
                
            
                        Deep goel said: 
                         
                        1 decade ago
                
                This is a reversible equation
Here 1=X
c=1,b=1/4 & a=1/6
c+b+a=1360
X*(1+1/4+1/6)=1360
X *((12+3+2)/12)= 1360
By solving we get b=240.
                Here 1=X
c=1,b=1/4 & a=1/6
c+b+a=1360
X*(1+1/4+1/6)=1360
X *((12+3+2)/12)= 1360
By solving we get b=240.
                        Siddhu said: 
                         
                        1 decade ago
                
                I have got a simple substitution way of solving
A+B+C=1360
A=2/3B , B=1/4C(C=4B as we need B's share)
2/3B+B+4B=1360
B=240
                A+B+C=1360
A=2/3B , B=1/4C(C=4B as we need B's share)
2/3B+B+4B=1360
B=240
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