Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 6)
                   
                                       
                                6.
A sum of Rs. 1360 has been divided among A, B and C such that A gets 
 of what B gets and B gets 
 of what C gets. B's share is:
 
                                    
 of what B gets and B gets 
 of what C gets. B's share is:
Answer: Option
                                                    Explanation:
                                                Let C's share = Rs. x
| Then, B's share = Rs. | x | , A's share = Rs. | ![]()  | 
    2 | x | x | ![]()  | 
    = Rs. | x | 
| 4 | 3 | 4 | 6 | 
![]()  | 
    x | + | x | + x = 1360 | 
| 6 | 4 | 
![]()  | 
    17x | = 1360 | 
| 12 | 
  x = | 
    1360 x 12 | = Rs. 960 | 
| 17 | 
| Hence, B's share = Rs. | ![]()  | 
    960 | ![]()  | 
    = Rs. 240. | 
| 4 | 
Discussion:
34 comments Page 1 of 4.
                
                        Sabari said: 
                         
                        1 decade ago
                
                How 17x will come?
                
                        Somya said: 
                         
                        1 decade ago
                
                x/6 + x/4+ x/1 =1360
l.c.m of6,4 &1 is 12
so 2x + 3x+ 12x/12=1360
17x/12=1360
This way is comes 17x/12 sabri
                l.c.m of6,4 &1 is 12
so 2x + 3x+ 12x/12=1360
17x/12=1360
This way is comes 17x/12 sabri
                     (1)
                
            
                        Yuvaraj said: 
                         
                        1 decade ago
                
                How 12 will come?
                
                        Pavi said: 
                         
                        1 decade ago
                
                x/6+x/4+x/1=1360
(2x+3X+12x)/12=1360
HERE 12 IS LCM OF 2,4,1
                (2x+3X+12x)/12=1360
HERE 12 IS LCM OF 2,4,1
                        Siddhu said: 
                         
                        1 decade ago
                
                I have got a simple substitution way of solving
A+B+C=1360
A=2/3B , B=1/4C(C=4B as we need B's share)
2/3B+B+4B=1360
B=240
                A+B+C=1360
A=2/3B , B=1/4C(C=4B as we need B's share)
2/3B+B+4B=1360
B=240
                        Deep goel said: 
                         
                        1 decade ago
                
                This is a reversible equation
Here 1=X
c=1,b=1/4 & a=1/6
c+b+a=1360
X*(1+1/4+1/6)=1360
X *((12+3+2)/12)= 1360
By solving we get b=240.
                Here 1=X
c=1,b=1/4 & a=1/6
c+b+a=1360
X*(1+1/4+1/6)=1360
X *((12+3+2)/12)= 1360
By solving we get b=240.
                        Kiran said: 
                         
                        1 decade ago
                
                A:B = 2:3.
B:C = 1:4.
A:B:C = 2:3:12.
Total parts = 2+3+12+17 parts.
17 parts = 1360.
B's share is 3 parts.
Then (1360*3)/17.
= 240.
                B:C = 1:4.
A:B:C = 2:3:12.
Total parts = 2+3+12+17 parts.
17 parts = 1360.
B's share is 3 parts.
Then (1360*3)/17.
= 240.
                     (1)
                
            
                        Sure said: 
                         
                        1 decade ago
                
                How come B is equal 1/4(X) ?
                
                        Sunny said: 
                         
                        1 decade ago
                
                Every thing is ok but how can we calculate the 17?
                
                        Bhavana said: 
                         
                        1 decade ago
                
                To say the truth I didn't understand any of the methods. Can any one explain it clearly.
                Post your comments here:
 
            
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