Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 6)
6.
A sum of Rs. 1360 has been divided among A, B and C such that A gets 
of what B gets and B gets 
of what C gets. B's share is:
of what B gets and B gets of what C gets. B's share is:
Answer: Option
Explanation:
Let C's share = Rs. x
| Then, B's share = Rs. | x | , A's share = Rs. |  |
2 | x | x |  |
= Rs. | x |
| 4 | 3 | 4 | 6 |
 |
x | + | x | + x = 1360 |
| 6 | 4 |
 |
17x | = 1360 |
| 12 |
| x = |
1360 x 12 | = Rs. 960 |
| 17 |
| Hence, B's share = Rs. | |
960 | |
= Rs. 240. |
| 4 |
Discussion:
34 comments Page 1 of 4.
Shivam said:
1 decade ago
let C be x.
//B gets 1/4 of what C gets means(of means multiply).
//What is C, C=x,
B=1/4 * C i.e.(1/4 * x) =>x/4.
// A gets 2/3 of what B gets means.
// What is B, B=x/4.
A=2/3*B i.e.(2/3 * x/4) => x/6.
Adding all means A + B + C.
x/6 + x/4 + x.
Taking an LCM of 6,4 i.e. 12.
This means 2x+3x+12x/12 => 17x/12.
=>17x/12=1360 => x= 1360*12/17 i.e.=> x= 960.
Put In B Share(means x/4) i.e. =>960/4=240.
Got it.
//B gets 1/4 of what C gets means(of means multiply).
//What is C, C=x,
B=1/4 * C i.e.(1/4 * x) =>x/4.
// A gets 2/3 of what B gets means.
// What is B, B=x/4.
A=2/3*B i.e.(2/3 * x/4) => x/6.
Adding all means A + B + C.
x/6 + x/4 + x.
Taking an LCM of 6,4 i.e. 12.
This means 2x+3x+12x/12 => 17x/12.
=>17x/12=1360 => x= 1360*12/17 i.e.=> x= 960.
Put In B Share(means x/4) i.e. =>960/4=240.
Got it.
Vishal said:
1 decade ago
Lets we do this problem in ratio method.
Given B gets 1/4 what of what c gets & A gets 2/3 of what B gets,
Lets c gets x, then B = x/4, then a gets 2/3(x/4) = x/6.
Hence A: B: C = x/6 : x/4 : x.
Hence A: B: C: = 2:3:12.
There fore the share of B is 3/17(1360) = 240.
Given B gets 1/4 what of what c gets & A gets 2/3 of what B gets,
Lets c gets x, then B = x/4, then a gets 2/3(x/4) = x/6.
Hence A: B: C = x/6 : x/4 : x.
Hence A: B: C: = 2:3:12.
There fore the share of B is 3/17(1360) = 240.
(1)
Shivani said:
7 years ago
A +B + C =1360.............(eq1)
A = 2/3 B.............(eq2)
B =1/4 C...............(eq3).
So, simplify C in terms of B bcz we have to find B's share.
;C =4B.
Now put this values in eq 1.
2/3B +B + 4B =1360,
On taking l.c.m.
2B +3B+ 12B =4080,
17 B = 4080,
B =4080/17,
B =240.
A = 2/3 B.............(eq2)
B =1/4 C...............(eq3).
So, simplify C in terms of B bcz we have to find B's share.
;C =4B.
Now put this values in eq 1.
2/3B +B + 4B =1360,
On taking l.c.m.
2B +3B+ 12B =4080,
17 B = 4080,
B =4080/17,
B =240.
(6)
Chandrika said:
4 years ago
A+B+C=1360-->1.
We don't know the c value.
Let us assume C=x.
A=2/3*B.
B=(1/4) *C.
=(1/4)*x=>x/4.
A=2/3*x/4=>2x/12=>x/6.
From 1,A+B+C=1360.
x/6+x/4+x=1360=>(2x+3x+12x)/12=1360.
17x=1360*12=>x=(1360*12)/17=>960,
B=x/4=>960/4=>Rs.240.
We don't know the c value.
Let us assume C=x.
A=2/3*B.
B=(1/4) *C.
=(1/4)*x=>x/4.
A=2/3*x/4=>2x/12=>x/6.
From 1,A+B+C=1360.
x/6+x/4+x=1360=>(2x+3x+12x)/12=1360.
17x=1360*12=>x=(1360*12)/17=>960,
B=x/4=>960/4=>Rs.240.
(4)
K.sumana said:
4 years ago
Given x + y + z = 1360.
x = 2/3(y)],
y = 1/4(z),
z = 4y.
Substitute x value and z value in eqn;
we get,
2/3(y) + y + 4y = 1360,
2/3(y) + 5y = 1360,
17/3(y) = 1360,
y = 240.
x = 2/3(y)],
y = 1/4(z),
z = 4y.
Substitute x value and z value in eqn;
we get,
2/3(y) + y + 4y = 1360,
2/3(y) + 5y = 1360,
17/3(y) = 1360,
y = 240.
(8)
Baburam said:
7 years ago
Take lcm of 2,3,5,4 = 60,
Now c get 60,
B get 1/4 of b 1/4*60=15.
A get 2/3 of b get 2/3*15=10,
Now the ratio of a b c is 2:3:12,
Then B share is 3/17*1360=240.
Now c get 60,
B get 1/4 of b 1/4*60=15.
A get 2/3 of b get 2/3*15=10,
Now the ratio of a b c is 2:3:12,
Then B share is 3/17*1360=240.
(2)
Deep goel said:
1 decade ago
This is a reversible equation
Here 1=X
c=1,b=1/4 & a=1/6
c+b+a=1360
X*(1+1/4+1/6)=1360
X *((12+3+2)/12)= 1360
By solving we get b=240.
Here 1=X
c=1,b=1/4 & a=1/6
c+b+a=1360
X*(1+1/4+1/6)=1360
X *((12+3+2)/12)= 1360
By solving we get b=240.
Kiran said:
1 decade ago
A:B = 2:3.
B:C = 1:4.
A:B:C = 2:3:12.
Total parts = 2+3+12+17 parts.
17 parts = 1360.
B's share is 3 parts.
Then (1360*3)/17.
= 240.
B:C = 1:4.
A:B:C = 2:3:12.
Total parts = 2+3+12+17 parts.
17 parts = 1360.
B's share is 3 parts.
Then (1360*3)/17.
= 240.
(1)
MathGenius said:
8 years ago
HOW 17 COMES?
All explanations did explain clearly how 17 come, ok 12 is the LCM of 6 and 4 down, but up there x+x+X so it turns to 17 x.
All explanations did explain clearly how 17 come, ok 12 is the LCM of 6 and 4 down, but up there x+x+X so it turns to 17 x.
(2)
Siddhu said:
1 decade ago
I have got a simple substitution way of solving
A+B+C=1360
A=2/3B , B=1/4C(C=4B as we need B's share)
2/3B+B+4B=1360
B=240
A+B+C=1360
A=2/3B , B=1/4C(C=4B as we need B's share)
2/3B+B+4B=1360
B=240
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