Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 6)
6.
A sum of Rs. 1360 has been divided among A, B and C such that A gets of what B gets and B gets of what C gets. B's share is:
Rs. 120
Rs. 160
Rs. 240
Rs. 300
Answer: Option
Explanation:

Let C's share = Rs. x

Then, B's share = Rs. x ,   A's share = Rs. 2 x x = Rs. x
4 3 4 6

x + x + x = 1360
6 4

17x = 1360
12

x = 1360 x 12 = Rs. 960
17

Hence, B's share = Rs. 960 = Rs. 240.
4

Discussion:
34 comments Page 2 of 4.

Vishal said:   1 decade ago
Lets we do this problem in ratio method.

Given B gets 1/4 what of what c gets & A gets 2/3 of what B gets,

Lets c gets x, then B = x/4, then a gets 2/3(x/4) = x/6.

Hence A: B: C = x/6 : x/4 : x.

Hence A: B: C: = 2:3:12.

There fore the share of B is 3/17(1360) = 240.
(1)

Kiran said:   1 decade ago
A:B = 2:3.

B:C = 1:4.

A:B:C = 2:3:12.

Total parts = 2+3+12+17 parts.

17 parts = 1360.

B's share is 3 parts.

Then (1360*3)/17.

= 240.
(1)

Sandilya said:   9 years ago
a + b + c = 1360,
a : b = 2 : 3,
b : c = 1 * 3 : 4 * 3 = 3 : 12.

So, 2 + 3 + 12 = 17.
then, 1360/17 = 80.

80 * 3 = 240.

Sabari said:   1 decade ago
How 17x will come?

Yuvaraj said:   1 decade ago
How 12 will come?

Pavi said:   1 decade ago
x/6+x/4+x/1=1360
(2x+3X+12x)/12=1360

HERE 12 IS LCM OF 2,4,1

Siddhu said:   1 decade ago
I have got a simple substitution way of solving

A+B+C=1360
A=2/3B , B=1/4C(C=4B as we need B's share)
2/3B+B+4B=1360
B=240

Deep goel said:   1 decade ago
This is a reversible equation

Here 1=X

c=1,b=1/4 & a=1/6

c+b+a=1360

X*(1+1/4+1/6)=1360
X *((12+3+2)/12)= 1360

By solving we get b=240.

Sure said:   1 decade ago
How come B is equal 1/4(X) ?

Sujay said:   8 years ago
How 17x will come? Please explain.


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