Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - Data Sufficiency 2 (Q.No. 1)
Directions to Solve
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
1.
What is the principal sum? | |
I. | The sum amounts to Rs. 690 in 3 years at S.I. |
II. | The sum amounts to Rs. 750 in 5 years at S.I. |
III. | The rate of interest is 5% p.a. |
Answer: Option
Explanation:
Clearly, any two of the three will give us the answer.
Correct answer is (E).
Discussion:
31 comments Page 3 of 4.
Vickma said:
9 years ago
AMOUNT = S. I + P.
690 - P = 3PR -> (1).
750 - P = 5PR -> (2).
Divide Eqn 2 by 1;
P = 600.
Use P = 600 in section I & III.
So, the correct option is 'E'.
690 - P = 3PR -> (1).
750 - P = 5PR -> (2).
Divide Eqn 2 by 1;
P = 600.
Use P = 600 in section I & III.
So, the correct option is 'E'.
T.Prabhu Pandiyan. said:
9 years ago
Anyone can please help me to understand the question.
(1)
Girish said:
9 years ago
690 - P = 3PR.
750 - p = 5PR.
Dividing both equations
(690 - P)/(750 - P) = 3/5.
-> (690 - P)5 = (750 - P)3.
By solving;
P = 600.
750 - p = 5PR.
Dividing both equations
(690 - P)/(750 - P) = 3/5.
-> (690 - P)5 = (750 - P)3.
By solving;
P = 600.
(3)
Shruthi said:
8 years ago
If it is any two of the 3 then there is a possibility of taking 1 and 2.
How can we get p using 1 and 2?
How can we get p using 1 and 2?
(1)
P V Snehil said:
8 years ago
We cannot get P using I and II, as we donot know the are when we have only these two statements.
Correct answer is D.
Correct answer is D.
(2)
Mansi Arora said:
8 years ago
Hi @Aryan,
We are using here all the three given statements to get the value of P which is not given in the options.
We are using here all the three given statements to get the value of P which is not given in the options.
Effoti said:
7 years ago
By using I and II;
S.I for 2 years = 750-690 = 60 as S.I is divided uniformly for each year, For 1 year = Rs. 30 and For 3 year = 90,
Principal = 690-90 = 600.
By using II and III
As Total Sum = Principal + Interest i.e 750 = P + I (after 5 years) ------> (1)
P = I *100 / R * T = I *100 / 5*5 = 4I,
Put value of P in eq. 1, 750 = 5I , I = 150 and P = 750 -150 = Rs. 600,
Similarly By using I and III.
P = I *100 / R*T = I*100/5*3 = 20/3(I),
690 = 20/3(I) + I , By solving this we get I = Rs.90 and P = 690 - 90 = Rs. 600.
Hence answer is E Any two of the three.
S.I for 2 years = 750-690 = 60 as S.I is divided uniformly for each year, For 1 year = Rs. 30 and For 3 year = 90,
Principal = 690-90 = 600.
By using II and III
As Total Sum = Principal + Interest i.e 750 = P + I (after 5 years) ------> (1)
P = I *100 / R * T = I *100 / 5*5 = 4I,
Put value of P in eq. 1, 750 = 5I , I = 150 and P = 750 -150 = Rs. 600,
Similarly By using I and III.
P = I *100 / R*T = I*100/5*3 = 20/3(I),
690 = 20/3(I) + I , By solving this we get I = Rs.90 and P = 690 - 90 = Rs. 600.
Hence answer is E Any two of the three.
Vidya sree said:
5 years ago
Thank you @Ashish.
Manthan said:
5 years ago
As Amount = principal+ SI.
Where si= prt/100.
This is the basic formulae that are applied here.
If suppose we take equationn 1 and 2 then,
P + P.3.r% = 690---(1)
P + P.5.r% = 750---(2)
Divide equation 1 by 2 to get r and then p,
And if we take eqn 1 and eqn 3 we will get;
"P=(100*si)/(r*t) ".
Where si= prt/100.
This is the basic formulae that are applied here.
If suppose we take equationn 1 and 2 then,
P + P.3.r% = 690---(1)
P + P.5.r% = 750---(2)
Divide equation 1 by 2 to get r and then p,
And if we take eqn 1 and eqn 3 we will get;
"P=(100*si)/(r*t) ".
(1)
Karuppaiya said:
4 years ago
As Simple as Like that, I will explain here;
Given as Statement 1: P = 690 N= 3 yrs.
Given as Statement 2: P = 750 N= 5 yrs.
By Using these statements We get SI for 2 yrs is (750-690 = 60).
Therefore; SI for 1 yr is 30.
So, SI for 3 yrs will be 90 and that of for 5 yrs will be 150.
We know that Amount = Principal + SI.
Here for 3 yrs W.K.T SI is 90 and Amount is 690.
and therefore Principal is 690-90=600.
And by using statements 2 and 3 we can solve by the following method.
P + (P*5*5)\100 = 750.
100P + 25P = 750*100.
125P = 75000.
P = 600.
Given as Statement 1: P = 690 N= 3 yrs.
Given as Statement 2: P = 750 N= 5 yrs.
By Using these statements We get SI for 2 yrs is (750-690 = 60).
Therefore; SI for 1 yr is 30.
So, SI for 3 yrs will be 90 and that of for 5 yrs will be 150.
We know that Amount = Principal + SI.
Here for 3 yrs W.K.T SI is 90 and Amount is 690.
and therefore Principal is 690-90=600.
And by using statements 2 and 3 we can solve by the following method.
P + (P*5*5)\100 = 750.
100P + 25P = 750*100.
125P = 75000.
P = 600.
(6)
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