Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - Data Sufficiency 2 (Q.No. 1)
Directions to Solve
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
1.
What is the principal sum? | |
I. | The sum amounts to Rs. 690 in 3 years at S.I. |
II. | The sum amounts to Rs. 750 in 5 years at S.I. |
III. | The rate of interest is 5% p.a. |
Answer: Option
Explanation:
Clearly, any two of the three will give us the answer.
Correct answer is (E).
Discussion:
31 comments Page 2 of 4.
Dass said:
1 decade ago
What is the basic formula for the sum?
9e tej said:
1 decade ago
Somebody please explain.
Manju said:
1 decade ago
Help needed in understanding division of equations!
Ashis said:
1 decade ago
In very simple level I explain to 9 how to get answer using ll & similarly only from (ll) we get P+S.I = 750 & T = 5.
And from (lll) we get R = 5.
Now P+(P*5*5)\100 = 750.
100P+25P = 750*100.
125P = 75000.
P = 600.
And from (lll) we get R = 5.
Now P+(P*5*5)\100 = 750.
100P+25P = 750*100.
125P = 75000.
P = 600.
Qwers said:
1 decade ago
There wasn't any information given with r% in the question (statements 1, 2). So I don't think taking are in both the cases is correct. So option D should be correct clarify.
Ashish said:
1 decade ago
For those who need help regarding how to divide equation I and II (as suggested by abcd).
750 = P+(P*R*5)/100 => 75000 = 100P + 5PR. (i).
690 = P+(P*R*3)/100 => 69000 = 100P + 3PR. (ii).
Subtracting (i) & (ii) , we get.
R = 3000/P.
Now substitute it in any one either (i) or (ii) , we get.
P = 600.
Thanks.
750 = P+(P*R*5)/100 => 75000 = 100P + 5PR. (i).
690 = P+(P*R*3)/100 => 69000 = 100P + 3PR. (ii).
Subtracting (i) & (ii) , we get.
R = 3000/P.
Now substitute it in any one either (i) or (ii) , we get.
P = 600.
Thanks.
Scientist said:
10 years ago
We can find answer using I and II as follows:.
5PR% = 750 - P.
3PR% = 690 - P --- Dividing them.
---------------.
5 750-P.
= 3 690-P.
3450 - 5P = 2250 - 3P.
1200 = 2P.
P = 600.
Using I and III.
I = PNR%.
5PR% = 750 - P.
3PR% = 690 - P --- Dividing them.
---------------.
5 750-P.
= 3 690-P.
3450 - 5P = 2250 - 3P.
1200 = 2P.
P = 600.
Using I and III.
I = PNR%.
Aman kumar shaw said:
9 years ago
How can we get the answer by using I and II. Please tell?
Aryan said:
9 years ago
I. Amount after 3 years = 690.
II. Amount after 5 years = 750.
Difference = SI for 2 years = 60.
SI for 1 year = 30,
SI for 3 years = 90,
SI for 5 years = 150,
Thus, Principal = 600.
II. Amount after 5 years = 750.
Difference = SI for 2 years = 60.
SI for 1 year = 30,
SI for 3 years = 90,
SI for 5 years = 150,
Thus, Principal = 600.
Kishor said:
9 years ago
Please explain that how to get the answer from eq 1 & 2 only.
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