Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - Data Sufficiency 2 (Q.No. 1)
Directions to Solve
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
1.
What is the principal sum? | |
I. | The sum amounts to Rs. 690 in 3 years at S.I. |
II. | The sum amounts to Rs. 750 in 5 years at S.I. |
III. | The rate of interest is 5% p.a. |
Answer: Option
Explanation:
Clearly, any two of the three will give us the answer.
Correct answer is (E).
Discussion:
31 comments Page 1 of 4.
Karuppaiya said:
4 years ago
As Simple as Like that, I will explain here;
Given as Statement 1: P = 690 N= 3 yrs.
Given as Statement 2: P = 750 N= 5 yrs.
By Using these statements We get SI for 2 yrs is (750-690 = 60).
Therefore; SI for 1 yr is 30.
So, SI for 3 yrs will be 90 and that of for 5 yrs will be 150.
We know that Amount = Principal + SI.
Here for 3 yrs W.K.T SI is 90 and Amount is 690.
and therefore Principal is 690-90=600.
And by using statements 2 and 3 we can solve by the following method.
P + (P*5*5)\100 = 750.
100P + 25P = 750*100.
125P = 75000.
P = 600.
Given as Statement 1: P = 690 N= 3 yrs.
Given as Statement 2: P = 750 N= 5 yrs.
By Using these statements We get SI for 2 yrs is (750-690 = 60).
Therefore; SI for 1 yr is 30.
So, SI for 3 yrs will be 90 and that of for 5 yrs will be 150.
We know that Amount = Principal + SI.
Here for 3 yrs W.K.T SI is 90 and Amount is 690.
and therefore Principal is 690-90=600.
And by using statements 2 and 3 we can solve by the following method.
P + (P*5*5)\100 = 750.
100P + 25P = 750*100.
125P = 75000.
P = 600.
(6)
HRK said:
4 years ago
Using I and III;
Let S.I be 'x'.
Hence, P = 690 - x.
x = [(690- x) *5*3] / 100.
Solve for 'x' and find P.
Similarly, it works using II and III
Now, using I and II.
Let x be the interest rate.
Hence, P + 3Px = 690, simplify to P(1+3x) =690 -----> (a)
P + 5Px = 750, simplify to P(1+5x)=750 -----> (b).
Now dividing a by b, P gets canceled and solves for x.
x = 0.05 or 5%.
Now substitute x in the equation a or b to get P.
So we can use any of the three to solve.
Thanks.
Let S.I be 'x'.
Hence, P = 690 - x.
x = [(690- x) *5*3] / 100.
Solve for 'x' and find P.
Similarly, it works using II and III
Now, using I and II.
Let x be the interest rate.
Hence, P + 3Px = 690, simplify to P(1+3x) =690 -----> (a)
P + 5Px = 750, simplify to P(1+5x)=750 -----> (b).
Now dividing a by b, P gets canceled and solves for x.
x = 0.05 or 5%.
Now substitute x in the equation a or b to get P.
So we can use any of the three to solve.
Thanks.
(3)
Girish said:
9 years ago
690 - P = 3PR.
750 - p = 5PR.
Dividing both equations
(690 - P)/(750 - P) = 3/5.
-> (690 - P)5 = (750 - P)3.
By solving;
P = 600.
750 - p = 5PR.
Dividing both equations
(690 - P)/(750 - P) = 3/5.
-> (690 - P)5 = (750 - P)3.
By solving;
P = 600.
(3)
P V Snehil said:
8 years ago
We cannot get P using I and II, as we donot know the are when we have only these two statements.
Correct answer is D.
Correct answer is D.
(2)
Manthan said:
5 years ago
As Amount = principal+ SI.
Where si= prt/100.
This is the basic formulae that are applied here.
If suppose we take equationn 1 and 2 then,
P + P.3.r% = 690---(1)
P + P.5.r% = 750---(2)
Divide equation 1 by 2 to get r and then p,
And if we take eqn 1 and eqn 3 we will get;
"P=(100*si)/(r*t) ".
Where si= prt/100.
This is the basic formulae that are applied here.
If suppose we take equationn 1 and 2 then,
P + P.3.r% = 690---(1)
P + P.5.r% = 750---(2)
Divide equation 1 by 2 to get r and then p,
And if we take eqn 1 and eqn 3 we will get;
"P=(100*si)/(r*t) ".
(1)
Aman said:
1 decade ago
According to third equation rate of interest is 5% so putting that in second equation that is p + p*rate*time/100 = sum.
p + p*5*5/100 = 750.
p + p*5*5/100 = 750.
(1)
Shruthi said:
8 years ago
If it is any two of the 3 then there is a possibility of taking 1 and 2.
How can we get p using 1 and 2?
How can we get p using 1 and 2?
(1)
T.Prabhu Pandiyan. said:
9 years ago
Anyone can please help me to understand the question.
(1)
Qwers said:
1 decade ago
There wasn't any information given with r% in the question (statements 1, 2). So I don't think taking are in both the cases is correct. So option D should be correct clarify.
Vidya sree said:
5 years ago
Thank you @Ashish.
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