Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
Discussion:
115 comments Page 9 of 12.
Kannan said:
1 decade ago
Hi @Gayathri,
Could you please explain it in your way? Your previous answer seems good.
Could you please explain it in your way? Your previous answer seems good.
King kartik (the king of dewas said:
1 decade ago
Can you answer me at what rate of simple interest will some amount be doubled in 5 years?
Bala said:
1 decade ago
Any one can solve it two or three line?
Vinoth kumar said:
1 decade ago
Here 3508 is a total interest.
Say 3500. 3500 is approximately 25% of 14000 (13900). So for one year it slightly more than 12.5%. So invest in A (14%) must be more.
So the answer must be less than 6950(13900/2). Two opinion A are B. Now pair up. (6400/7500) or (6500/7400).
Take any one pair find out their simple interest. And then add up both SI which result in 3508 is the answer.
Say 3500. 3500 is approximately 25% of 14000 (13900). So for one year it slightly more than 12.5%. So invest in A (14%) must be more.
So the answer must be less than 6950(13900/2). Two opinion A are B. Now pair up. (6400/7500) or (6500/7400).
Take any one pair find out their simple interest. And then add up both SI which result in 3508 is the answer.
Ashwini said:
1 decade ago
How to take rate percentages? Please explain me
Ganesh said:
1 decade ago
Someone's tell me how did you get 3508? Please answer me.
Phani Kumar said:
1 decade ago
Here the shortcut for this kind of problems.
P1 = ((100*I) - (P*T*R2))/(difference of R1 and R2). And then find P2 by:
P2 = P-P1.
Here,
P = 13900.
P1 = Part1;
P2 = Part2;
I = 3508;
T = 2;
R1 = 14;
R2 = 11;
P1 = ((100*I) - (P*T*R2))/(difference of R1 and R2). And then find P2 by:
P2 = P-P1.
Here,
P = 13900.
P1 = Part1;
P2 = Part2;
I = 3508;
T = 2;
R1 = 14;
R2 = 11;
Sou said:
1 decade ago
Its a heavy. Is there any shortcut?
R.srinivasulu said:
1 decade ago
Shortcut method tell me sir.
Teja said:
1 decade ago
See, it is given that both a&b together combinedly having principal amount of 13,900 for two years having si of 3508.
Now by adding both schemes si's with the total si given for two years by using formula
si = p*t*r/100.
By considering scheme b = 13,900-a,
We can find investment on b scheme.
Now by adding both schemes si's with the total si given for two years by using formula
si = p*t*r/100.
By considering scheme b = 13,900-a,
We can find investment on b scheme.
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