Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
Discussion:
115 comments Page 12 of 12.
Pp depu said:
1 decade ago
Can some one plese explain me the 2nd step 28X-22X = 350800 - (13900x22) how it came?
Vinod said:
1 decade ago
Suppose total simple interest of A & B is 13900*25%(14%+11%) =3475, but in problem total interest for 2 years is 3508, difference amount is Rs.33/-,can some one explain me, why this differnce has come ?
Suchita said:
1 decade ago
@Rajesh.
Can you please tell me that method.
Can you please tell me that method.
Rajesh said:
1 decade ago
Use the method of alligation.
Venu said:
1 decade ago
Can any one solve this in simple way?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers