Aptitude - Simple Interest
Exercise : Simple Interest - General Questions
- Simple Interest - Formulas
- Simple Interest - General Questions
- Simple Interest - Data Sufficiency 1
- Simple Interest - Data Sufficiency 2
1.
A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
Answer: Option
Explanation:
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
3.
A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?
Answer: Option
Explanation:
| Principal |
|
|||||
|
||||||
| = Rs. 8925. |
4.
How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
Answer: Option
Explanation:
5.
Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?
Answer: Option
Explanation:
Let rate = R% and time = R years.
| Then, | |
1200 x R x R | |
= 432 |
| 100 |
12R2 = 432
R2 = 36
R = 6.
Video Explanation: https://youtu.be/TjjI4iRkzT0
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