Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 5)
5.
Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?
Answer: Option
Explanation:
Let rate = R% and time = R years.
Then, | ![]() |
1200 x R x R | ![]() |
= 432 |
100 |
12R2 = 432
R2 = 36
R = 6.
Video Explanation: https://youtu.be/TjjI4iRkzT0
Discussion:
62 comments Page 1 of 7.
Josvalilly said:
8 months ago
Principal always 100%.
The value of principal = 1200.
SI value = 432.
Rate% * no.of year = SI%.
100% = 1200.
? = 432.
Only divide the same row or the same column. Cross only for multiplication.
Then, R = 6.
The value of principal = 1200.
SI value = 432.
Rate% * no.of year = SI%.
100% = 1200.
? = 432.
Only divide the same row or the same column. Cross only for multiplication.
Then, R = 6.
(2)
Sakamuri veera Brahmanjaneyulu said:
11 months ago
The simple interest for as many years as the rate of interest means;
Let the rate of interest is 12% then the period is 12 years.
so, principle amount(p) = 1200
SI = 432
r = r.
t = r.
SI = ptr/100.
432 = 1200 * r * r/100.
r^2 = 36,
r = 6.
Let the rate of interest is 12% then the period is 12 years.
so, principle amount(p) = 1200
SI = 432
r = r.
t = r.
SI = ptr/100.
432 = 1200 * r * r/100.
r^2 = 36,
r = 6.
(3)
KARTHIKEYAN said:
1 year ago
S.I = P * R * T/100.
1200 * R * T/100 = 432.
Let us calculate for one year;
1200 * r * 1 = 432 * 100,
r = 432 * 100/1200 * 1,
r = 6.
1200 * R * T/100 = 432.
Let us calculate for one year;
1200 * r * 1 = 432 * 100,
r = 432 * 100/1200 * 1,
r = 6.
(12)
SURAJ DALAVI said:
2 years ago
If considered, the interest rate = 3.6%.
Then one year interest is = 1200 x 3.6% = 43.2/-.
As per the simple interest rule he paid interest for 10 years = 43.2 x 10 years = 432.
How 3.6% interest is not correct answer please explpain, because in the question there is not mention of how many years he paid interest rs. 432?
Please explain.
Then one year interest is = 1200 x 3.6% = 43.2/-.
As per the simple interest rule he paid interest for 10 years = 43.2 x 10 years = 432.
How 3.6% interest is not correct answer please explpain, because in the question there is not mention of how many years he paid interest rs. 432?
Please explain.
(8)
Tukundane Benard said:
3 years ago
How? Please explain to me the answer.
(3)
C Madhuri said:
3 years ago
Principal = Rs.1200.
Interest = Rs.432.
Rate of interest = x%p.a.
Given the rate of interest=time duration = x.
A = P+I = Rs.1200 + Rs.432 = Rs.1632
A = P[1+(R*T/100)]
1632 = 1200[1+(x*x/100)]
1632 = 1200[1+(x^2/100)]
1632 = 1200/100(x^2+100)
1632 = 12(x^2+100)
136-100 = x^2.
36 = x^2.
x = 6.
Rate of interest = 6%p.a.
Interest = Rs.432.
Rate of interest = x%p.a.
Given the rate of interest=time duration = x.
A = P+I = Rs.1200 + Rs.432 = Rs.1632
A = P[1+(R*T/100)]
1632 = 1200[1+(x*x/100)]
1632 = 1200[1+(x^2/100)]
1632 = 1200/100(x^2+100)
1632 = 12(x^2+100)
136-100 = x^2.
36 = x^2.
x = 6.
Rate of interest = 6%p.a.
(9)
Jagadeesh said:
3 years ago
Here Amount * 100 = principle * time* rate is a simple formula for si.
432*100 = 1200*t*r.
43200/1200 = t*r.
36 = t*r.
Here t=r given;
So r=6 and t=6.
432*100 = 1200*t*r.
43200/1200 = t*r.
36 = t*r.
Here t=r given;
So r=6 and t=6.
(12)
Sulthan shareef said:
3 years ago
1200 * R * R/100 = 432.
12R * R = 432,
R * R = 432/12,
R * R = 36,
R = 36/2,
R = 6.
12R * R = 432,
R * R = 432/12,
R * R = 36,
R = 36/2,
R = 6.
(6)
Jeetesh kella said:
3 years ago
I am not getting this one. Please clarify the formula, clearly.
(5)
Manikandan said:
4 years ago
@All.
The question is a little tricky.
[many years as the rate of interest] this means;
[Many years= rates of interest].
Therefore we can take anyone as a,x,t,n,r etc.
Years=rate of interest= X ----------> Eqn.(1)
We can also take the T alternative of X.
Then we solve the ans.
S.I=PTR/100.
We didn't know the value of T&R so move to the left side.
TR=(S.I * 100)/P
From Eqn. 1 we know that T&R are the same.
X*X=(S.I*100)/P.
P=principal= sum=1200.
S.I=Simple interest=432.
X^2=(432*100)/1200,
X^2=43200/1200,
X^2=432/12,
X^2=36.
X=√36.
X=6.
The question is a little tricky.
[many years as the rate of interest] this means;
[Many years= rates of interest].
Therefore we can take anyone as a,x,t,n,r etc.
Years=rate of interest= X ----------> Eqn.(1)
We can also take the T alternative of X.
Then we solve the ans.
S.I=PTR/100.
We didn't know the value of T&R so move to the left side.
TR=(S.I * 100)/P
From Eqn. 1 we know that T&R are the same.
X*X=(S.I*100)/P.
P=principal= sum=1200.
S.I=Simple interest=432.
X^2=(432*100)/1200,
X^2=43200/1200,
X^2=432/12,
X^2=36.
X=√36.
X=6.
(11)
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